I'；我试图将我的表单链接到我的PHP页面，我想打印出用户'；当他点击提交按钮时，他在该页面上的输入 - I'm trying to link my form to my PHP page, and I want to print out the user's input onto that page when he clicks the submit button

I'm trying to link my form to my PHP page, and I want to print out the user's input onto that page when he clicks the submit button

我曾尝试在表单中使用GET方法，在PHP页面中使用$_GET方法，但它并没有将两者链接在一起。当用户单击提交按钮时，我想打印出用户输入的表单中的元素。这是我用于表单的代码：

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>MY Form</title>
</head>
<body>
    <form action="q4.php" method="get">
      <label><b>First Name:</b></label><br />
      <input type="text" name="first_name"><br />
      <label><b>Last Name:</b></label><br />
      <input type="text" name="second_name">
        <br>
        <label for="status">Status</label><br>
        <select name="status" id="status">
        <option value="undergraduate">UnderGraduate</option>
        <option value="postgraduate">Postgraduate</option>
        <option value="alumni">Alumni</option>
        </select>
        <br><br><br>
        <input type="radio" name="continuing">Continuing<br>
        <input type="radio" name="continuing">Not Continuing<br>
        <br><br>
        <label>Satisfaction Level <br></label>
        <label>0</label><input type="range" name="satisfaction" min="0" max="100"/><label>100</label>
        <br><br>
        <input type="submit" value="Submit">
    </form>
</body>
</html>

以下是我在PHP中使用的代码：

<?php
$names = array(first_name => '', second_name => '');
reset($names);
while (list($key, $val) = each($names)) {
    echo "$key => $_GET'n";
}
?>

如果你想打印出所有结果，你可以做一些类似的事情

<?php
foreach($_GET as $key => $value){
echo $key.": ".$value;
}
?>

但如果你只想显示特定的数据，那么可能会像这个一样

<?php
$names = array(first_name => '$_GET['first_name']', second_name => 'second_name');
foreach($names as $name => $value){
echo $name.": ".$value;
}
?>