我正在尝试从包含以下代码的php文件中检索信息。我的代码包含列电子邮件、名字、姓氏和州。
$query = 'SELECT * FROM users WHERE LOWER(Email) = :email';
$stmt = $dbh->prepare($query);
$stmt->bindValue(':email', $email);
$stmt->execute();
if ($stmt->rowCount() == 1) {
$row = $stmt->fetch(PDO::FETCH_ASSOC);
$firstName = $row['FirstName'];
$lastName = $row['LastName'];
$state = $row['State'];
} echo json_encode($row);
我的 Ajax 代码是：
$.ajax({
datatype: 'json',
type: "POST",
url: 'json-data.php',
success: function(data) {
//called when successful
$('#firstname').append(data.FirstName);
},
error: function(e) {
//called when there is an error
//console.log(e.message);
}
}）;
当我键入 $('#firstname').append(data); 时，它向我显示以下输出：
{"FirstName":"Foo","LastName":"Bar","State":"Florida","Email":"foo@bar.com"}
如何做到这一点，以便我只能获取名字并将其附加到div？
尝试：
var obj = jQuery.parseJSON(data);
$('#firstname').append(OBJ.FirstName);