我对select选项有问题。我想用具有相同id的many-select选项显示n隐藏我的表ndiv，但结果仅在first-select选项中有效。我真的需要你的帮助，这样我所有的选择都可以使用相同的id。帮帮我，伙计们。。！…
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script>
<script type="text/javascript">
$(function() {
$('#sts').change(function() {
$('div.number').hide();
$('table.number').hide();
$('#number' + $(this).val()).show();
}).change();
});
</script>
<select name="" id="sts" class="form-select required">
<option value="">- select -</option>
<option value="1">Option 1</option>
<option value="2">Option 2</option>
<option value="3">Option 3</option>
<option value="4">Option 4</option>
</select>
<select name="" id="sts" class="form-select required">
<option value="">- select -</option>
<option value="1">Option 1</option>
<option value="2">Option 2</option>
<option value="3">Option 3</option>
<option value="4">Option 4</option>
</select>
<div id="number1" class="number">Option 1</div>
<div id="number2" class="number">Option 2</div>
<div id="number3" class="number">Option 3</div>
尝试
$('*#sts').change(function() {...});
通常HTML元素的id属性必须是唯一的。所以请将代码更改为
<select name="" id="sts" class="form-select required">
<option value="">- select -</option>
<option value="1">Option 1</option>
<option value="2">Option 2</option>
<option value="3">Option 3</option>
<option value="4">Option 4</option>
</select>
<select name="" id="sts1" class="form-select required">
<option value="">- select -</option>
<option value="1">Option 1</option>
<option value="2">Option 2</option>
<option value="3">Option 3</option>
<option value="4">Option 4</option>
</select>
<div id="number1" class="number">Option 1</div>
<div id="number2" class="number">Option 2</div>
<div id="number3" class="number">Option 3</div>
现在使用代码通过their class名称获取select元素来进行处理：
<script type="text/javascript">
$('select.form-select').change(function() {
$('div.number').hide();
$('table.number').hide();
$('#number' + $(this).val()).show();
});
</script>