在roompage.php页面上，我有如下数据：
<?php $form = ActiveForm::begin(['action' =>['site/checkout'],'method' => 'POST']); ?>
<?= $form->field($model, 'room_type')->hiddenInput(['value'=>$data->room_type])->label(false); ?>
<?= $form->field($model, 'rate')->hiddenInput(['value'=>$data->rate])->label(false); ?>
<?= Html::submitButton('CHECKOUT', ['class' => 'button btn btn-default']) ?>
<?php ActiveForm::end(); ?>
我需要将这些数据传递到checkout.php页面如何做到这一点？我可以通过URL发送数据吗？如果是，那么如何做到这一点，或者以任何其他方式做到同样的事情？
public function actionCheckout()
{
$model = new CreateBookings();
$data = Yii::$app->request->post();
if(isset($data['DynamicModel']))
{
$room_type = $data['DynamicModel']['room_type'];
}
if ($model->load(Yii::$app->request->post()))
{
$model->save();
return $this->redirect('confirmation');
}
else
{
return $this->render('checkout', [
'model' => $model,'room_type' => $room_type]);
}
}
public function actionRoompage($room_id)
{ $model = new 'yii'base'DynamicModel(['room_type','rate']);
$searchModel = new RoomTypesSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
$data = RoomTypes::find()->where(['room_id' => $room_id])->one();
return $this->render('roompage', [
'dataProvider' => $dataProvider,
'searchModel' => $searchModel,
'data' => $data,
]);
}
需要将数据从actionRoompage()传递到actionCheckout()
在这种情况下，您应该使用POST请求将一些数据发送到另一个页面。在actionCheckout中，您已经准备好获取POST数据并将其加载到型号$model->load(Yii::$app->request->post()) 中
您还需要在视图roompage.php中创建表单例如，在您的actionRoompage中还创建$model = new CreateBookings();
并且比在视图中显示输入（您可以使它们隐藏）：
<?php $form = ActiveForm::begin(['id' => 'checkout-form']); ?>
<?php echo $form->field($model, 'quantity') ?>
<?php echo $form->field($model, 'email') ?>
<?php echo Html::submitButton(Yii::t('frontend', 'Login'), ['class' => 'btn btn-primary', 'name' => 'login-button']) ?>
<?php ActiveForm::end(); ?>