因此，在post_action.php中，我有一堆div被回显，以测试我是否在ajax请求期间访问了该文件。当我点击.deletePost时，我会收到一条警告，说"已成功删除"，这让我相信ajax请求正在工作，但post_action.php中内容为"hello world"的div不存在。有什么想法吗？
post_action.php
<?php
include 'db_connect.php';
include 'functions.php';
sec_session_start();
echo "<div>Hello World</div>";
echo "<div>Hello World</div>";
echo "<div>Hello World</div>";
echo "<div>Hello World</div>";
if($_GET['action'] == "deletePost")
deletePost($_GET['postTitle']);
function deletePost($title){
$sql = "DELETE FROM blog WHERE Title = '$title'";
mysqli_query($mysqli, $sql);
}
?>
functions.php
<?php
function sec_session_start() {
$session_name = 'sec_session_id'; // Set a custom session name
$secure = false; // Set to true if using https.
$httponly = true; // This stops javascript being able to access the session id.
ini_set('session.use_only_cookies', 1); // Forces sessions to only use cookies.
$cookieParams = session_get_cookie_params(); // Gets current cookies params.
session_set_cookie_params($cookieParams["lifetime"], $cookieParams["path"], $cookieParams["domain"], $secure, $httponly);
session_name($session_name); // Sets the session name to the one set above.
session_start(); // Start the php session
session_regenerate_id(); // regenerated the session, delete the old one.
}
?>
dbconnect.php
<?php
$host="localhost"; // Host name
$username="root"; // username
$password="********"; // password
$dbname="nightowl"; // Database name
$tblname="blog"; // Table name
$mysqli=mysqli_connect($host,$username,$password,$dbname);
mysql_connect("$host", "$username", "$password");
mysql_select_db("$dbname");
?>
Javascript
$(document).ready(function(){
$('.deletePost').click(function(){
$.ajax({
url:"scripts/post_action.php",
data: {action: "deletePost", postTitle: $(this).siblings("h3.blog").text()},
success: function(){
alert('DELETED SUCCESSFULLY');
}
});
});
});
在HTML中，您必须首先准备一个元素（在本例中为div）：
<div id='container'>
</div>
然后你的成功ajax：
success: function(response){ //retrieves the return from php
$("#container").html(response); //put the return inside the element that has id = container
alert('DELETED SUCCESSFULLY');
}
所以，你的：
echo "<div>Hello World</div>";
echo "<div>Hello World</div>";
echo "<div>Hello World</div>";
echo "<div>Hello World</div>";
将显示在id为container的div内
要使php post_actions.php脚本中的div出现，您需要执行以下操作：
success: function(response){
$("#containerWhereDivsCome").html(response);
alert('DELETED SUCCESSFULLY');
}