我使用Yii2高级模板。在我的数据库表中,我有带有categry
字段(从1..到inf)的项目
控制器动作:
public function actionIndex()
{
$searchModel = new AdsSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
return $this->render('index', [
'searchModel' => $searchModel,
'dataProvider' => $dataProvider,
]);
}
视图:
<?= ListView::widget([
'dataProvider' => $dataProvider,
'itemOptions' => ['class' => 'item'],
'itemView' => '_item_view',,
]) ?>
我已启用prettyUrl
'urlManager' => [
'enablePrettyUrl' => true,
'showScriptName' => false,
],
和.htaccess在前端/web/
RewriteEngine on
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule . index.php
1) 如何显示仅按类别找到的项目?现在mysite.com/items显示混合类别的所有项目我想制作mysite.com/items/cat/1或mysite.com/items/1,用category = 1
显示类别
2) 有没有关于如何将mysite.com/items/category-name-url改为数字的文章?我将类别名称存储在$app->params
中。id = 5
的下一个项目页面将是mysite.com/items/category-name-url/5
1)在urlManager
的配置中放入:
'items/cat/<id:'d+>' => '{YOUR_CONTROLLER}/{YOUR_ACTION}',
在类似的controller
中:
public function actionIndex($id) // yii2 provide $id form url
{
$dataProvider = new ActiveDataProvider([
'query' => AdsSearch::find()->where(['category' => $id]),
'pagination' => [
'pageSize' => 20,
],
]);
return $this->render('index', [
'dataProvider' => $dataProvider,
'category' => $category
]);
}
2) 在urlManager
的配置中输入:
'items/<category>' => '{YOUR_CONTROLLER}/{YOUR_ACTION}',
在controller
中
$subCategory = Yii::$app->request->get('category');
$dataProvider = new ActiveDataProvider([
'query' => AdsSearch::find()->where(['categoryUrl' => $subCategory]),
'pagination' => [
'pageSize' => 20,
],
]);
return $this->render('index', [
'dataProvider' => $dataProvider,
'category' => $category
]);
或者在我的项目中,比如Category
和Goods
型号:
$category = Category::findOne(['url' => $subCategory]);
$dataProvider = new ActiveDataProvider([
'query' => Goods::find()->where(['categoryId' => $category->id])->with('mainPhoto'),
'pagination' => [
'pageSize' => 20,
],
]);
return $this->render('index', [
'dataProvider' => $dataProvider,
'category' => $category
]);