只读pdf文件，并在目录中获取该pdf文件的文件名 - Read only pdf files and get the filename of that pdf files in a directory

Read only pdf files and get the filename of that pdf files in a directory

本文关键字：文件 pdf 获取文件名只读 | 更新日期: 2023-12-02

我需要只读取目录中的pdf文件，然后读取每个文件的文件名，然后我将使用该文件名重命名一些txt文件。我试过只使用eregi函数。但它似乎无法阅读我所需要的全部内容。如何把它们读好？这是我的代码：

$savePath   ='D:/dir/';
$dir       = opendir($savePath);
$filename  = array();
while ($filename = readdir($dir)) {
if (eregi("'.pdf",$filename)){
    $read = strtok ($filename,"."); //get the filenames
//to rename some txt files using the filenames that I get before
//$testfile is text files that I've read before
    $testfile = "$read.txt";
    $file = fopen($testfile,"r") or die ('cannot open file');
    if (filesize($testfile)==0){} 
    else{
        $text = fread($file,55024);
        fclose($file);
        echo "</br>"; echo "</br>";         
    }
}

更优雅：

foreach (glob("D:/dir/*.pdf") as $filename) {
    // do something with $filename
}

只获取文件名：

foreach (glob("D:/dir/*.pdf") as $filename) {
    $filename = basename($filename);
    // do something with $filename
}

您可以通过筛选文件类型来完成此操作。。以下是示例代码。

<?php 
// directory path can be either absolute or relative 
$dirPath = '.'; 
// open the specified directory and check if it's opened successfully 
if ($handle = opendir($dirPath)) { 
   // keep reading the directory entries 'til the end 
   $i=0; 
   while (false !== ($file = readdir($handle))) { 
   $i++; 
      // just skip the reference to current and parent directory 
      if (eregi("'.jpg",$file) || eregi("'.gif",$file) || eregi("'.png",$file)){ 
         if (is_dir("$dirPath/$file")) { 
            // found a directory, do something with it? 
            echo " [$file]<br>"; 
         } else { 
            // found an ordinary file 
            echo $i."- $file<br>"; 
         } 
      } 
   } 
   // ALWAYS remember to close what you opened 
   closedir($handle); 
}  
?>

上面演示了与图像相关的文件类型，您可以对.PDF文件执行同样的操作。

此处更好地解释