我正在尝试将LinkedIn API中的数据插入到MySql数据库中。
我的PHP代码正在从不在第二级的数组中获取所有值。我不知道如何解释这一点，但我将包括下面的数组结构：
Array
(
[person] => Array
(
[id] => ########
[first-name] => ########
[last-name] => ########
[languages] => Array
[skills] => Array
(
[skill] => Array
(
[id] => 1
[skill] => Array
(
[name] => Start-ups
)
[0] => Array
(
[id] => 2
[skill] => Array
(
[name] => Business Strategy
)
)
[1] => Array
(
[id] => 3
[skill] => Array
(
[name] => Marketing Strategy
)
)
[2] => Array
(
[id] => 12
[skill] => Array
(
[name] => Management
)
)
)
)
[email-address] => ########
[phone-numbers] => ########
[im-accounts] => ########
[twitter-accounts] => ########
[headline] => ########
[picture-url] => ########
[public-profile-url] => ########
)
)
我的PHP代码如下：
/* SKILLS */
// An array to hold it temporarily
$skills_arr = array();
foreach ($array->skills->skill as $t) {
// Cast it to a string to get the text value back
$skills_arr[] = (string)$t;
}
// Implode the array to a string
$skills = implode(', ', $skills_arr);
我需要的是获得所有的"技能"，并用逗号"，"分隔它们。
如果我的代码有效，我会得到以下值：$skills="初创企业、商业战略……"
想法？
您可以为此使用嵌套的Foreach循环。像
$skills_arr = array();
foreach($array['person']['skills']['skill'] as $val)
{
foreach($val['skill'] as $res)
{
$skills_arr[] = $res['name'];
}
}
echo $skills = implode(', ', $skills_arr);