这是我的事件编码。我希望它在我的系统中显示事件属性。错误显示为
致命错误：函数名称必须是中的字符串D： ''XAMPP''htdocs''system''bulletin.php
函数名必须是字符串意味着什么？错误在哪里？我该换哪条线？
<th scope="col"><center><strong>Event ID</strong></center></th>
<th scope="col"><center><strong>Event</strong></center></th>
<th scope="col"><center><strong>Description of the Event</strong></center></th>
<?php
require 'database.php';
$qry = "SELECT * FROM bulletin ORDER BY event_id DESC";
$result = mysql_query($qry) OR die (mysql_error());
while($row = mysql_fetch_assoc($result())){
$event_id = $row['event_id'];
$event = $row['event'];
$venue = $row['venue'];
$daydropdown_start = $row['day1'];
$monthdropdown_start = $row['month1'];
$yeardropdown_start = $row['year1'];
}
<td><? echo $row['event_id']; ?></td>
<td><? echo $row['event']; ?></td>
<td><br>Venue:<?php echo $row['venue']; ?></br>
<br> Date: <?php echo $row['day1'] / $row['month1'] / $row['year1']; ?> </br></td>
我猜您的错误在这行while($row = mysql_fetch_assoc($result())){ 中
$result不是一个函数，而是一个变量。将其更改为
while($row = mysql_fetch_assoc($result)){，你应该是好