这是我的login.php
<?php
//load and connect to MySQL database stuff
require("config.inc.php");
if (!empty($_POST)) {
if(empty($_POST['username']) || empty($_POST['password'])) {
$response["success"] = 0;
$response["message"] = "Please fill in the login details!";
die(json_encode($response));
}
$query = "SELECT email, password, position FROM user WHERE email = :email ";
$query_params = array(':email' => $_POST['username'],);
try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
// For testing, you could use a die and message.
//die("Failed to run query: " . $ex->getMessage());
//or just use this use this one to product JSON data:
$response["success"] = 0;
$response["message"] = "Database Error1. Please Try Again!";
die(json_encode($response));
}
//This will be the variable to determine whether or not the user's information is correct.
//we initialize it as false.
$validated_info = false;
$login_ok = false;
//fetching all the rows from the query
$row = $stmt->fetch();
if ($row) {
//if we encrypted the password, we would unencrypt it here, but in our case we just
//compare the two passwords
if ($_POST['password'] === $row['password']) {
$login_ok = true;
}
// If the user logged in successfully, then we send them to the private members-only page
// Otherwise, we display a login failed message and show the login form again
if ($login_ok) {
$response["success"] = 1;
$response["message"] = "Login Successful!";
$response["posts"] = array();
foreach ($row as $rerow) {
$row = array(
$post["position"] = $rerow["position"]
);
array_push($response["posts"], $post);
}
die(json_encode($response));
}
else {
$response["success"] = 0;
$response["message"] = "Invalid Credentials!";
die(json_encode($response));
}
}
}
else {
?>
<h1>Login</h1>
<form action="login.php" method="post">
Username:<br />
<input type="text" name="username" placeholder="username" />
<br /><br />
Password:<br />
<input type="password" name="password" placeholder="password" value="" />
<br /><br />
<input type="submit" value="Login" />
</form>
<a href="register.php">Register</a>
<?php
}
?>
警告出现三次，同时显示
｛"成功"：1，"消息"："登录成功
我正确输入了我的登录id和密码，我想从我的数据库中检索值为"user"的位置，为什么它只显示j 1 u。
$row = array(
$post["position"] = $rerow["position"]
);
应该是
$row = array(
$post["position"] => $rerow["position"]
);
事实上
foreach ($row as $rerow) {
$row = array(
$post["position"] = $rerow["position"]
);
array_push($response["posts"], $post);
}
也许你想做其他事情：
do {
$post = $row["position"]
array_push($response["posts"], $post);
} while ($row = $stmt->fetch());
这会将字段"position"添加到posts中，并继续获取其他记录。