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Search arrays then echo with conditionals?

我正在尝试做这样的事情:

  $random = array("apple","celery","banana");
  $define_fruits = array("apple","banana","pears","mango");
  $define_vegetables = array("celery","lettuce","carrots","cucumber");
  if($random contains only fruits){
    echo fruits;
  }elseif($random contains only vegetables){
    echo vegetables;
  }elseif($random contains both fruits and vegetables){
    echo both;
  }

解决:

$in_fruits = sizeof(array_intersect($random,$define_fruits));
$in_vegetables = sizeof(array_intersect($random,$define_vegetables));
      if($in_fruits >= 1 && $in_vegetables >= 1){
          echo "in_fruits and in_vegetables "; 
        }elseif($in_fruits === 0 && $in_vegetables >= 1){
          echo "in_fruits "; 
        }elseif($in_fruits >= 1 && $in_vegetables === 0){
          echo "in_fruits"; 
        }

级数:

$in_fruits = count(array_intersect($random,$define_fruits));
$in_vegetables = count(array_intersect($random,$define_vegetables));
if( $in_fruits ){
  if( $in_vegetables )
    echo "both";
  else
    echo "fruits";
}elseif( $in_vegetables ){
  echo "veggies";
}else{
  echo "neither ";

你可能想看看array_intersect:

http://php.net/manual/en/function.array-intersect.php

这可能会更有效地完成,但这是一种简单的方法:

$random = array("apple","celery","banana");
$define_fruits = array("apple","banana","pears","mango");
$define_vegetables = array("celery","lettuce","carrots","cucumber");
if( count(array_intersect($define_fruits,$random)) ){
  if( count(array_intersect($define_vegetables,$random)) )
    echo "both";
  else
    echo "fruit";
} elseif( count(array_intersect($define_vegetables,$random)) ){
  echo "vegetables";
} else {
  echo "neither";
}

最简单的解决方案是:

if ( in_array($define_fruits, $random) && ! in_array($define_vegetables, $random) ) {
   // Only fruits
}elseif ( ! in_array($define_fruits, $random) && in_array($define_vegetables, $random) ) {
   // Only Vegetables
}elseif ( in_array($define_fruits, $random) && in_array($define_vegetables, $random) ) {
   // Both fruits and vegetables
}