使用codeigniter 3分页时跳过表单验证

我有一个搜索表单，它接受7个不同的输入，并使用这些值从5个不同的表中查询数据。获取的行被返回到CodeIgniter控制器，以在视图中显示，但带有分页。

除了其他特定于输入的验证外，我还检查用户是否提供了7个字段中的至少一个值用于搜索。如果没有，那么我们抛出一个错误。

下面的代码运行良好，它查询数据并显示分页，但当我点击分页链接的第2页时，它会中断，因为控制器会重新加载搜索表单并执行表单验证，但失败了。

执行验证、获取数据和分页的控制器代码：

public function search_metadata_database()
{
    $arr = array();
    $data = $this->input->post();
    foreach ($data as $key => $value)
    {
        if($value)
        {
            $arr[$key] = $value;
        }
    }
    if(count($arr) < 1)
    {
        $this->session->set_flashdata('metadata_search_message', 'Please provide atleast one input!');
        redirect('Metadata/search_metadata_view');
    } 
    else 
    {
        if($this->form_validation->run() == FALSE)
        {
            $this->load->view('pages/metadataview/metadata_search');
            $this->load->view('pages/metadataview/metadata_form');
        }
        else
        {
            foreach ($arr as $key => $value)
            {
                $arr[$key] = $this->get_master_id_by_name($key,$value);
            }
            $this->load->helper('url');
            $this->load->library('pagination');
            $config['base_url'] = site_url('Metadata/search_metadata_database');
            $config['total_rows'] = $this->metadata_model->fetch_metadata_record_count($arr);
            $config['per_page'] = "2";
            $config["uri_segment"] = 2;
            $choice = $config["total_rows"] / $config["per_page"];
            $config["num_links"] = floor($choice);
            $config['full_tag_open'] = '<ul class="pagination">';
            $config['full_tag_close'] = '</ul>';
            $config['first_link'] = false;
            $config['last_link'] = false;
            $config['first_tag_open'] = '<li>';
            $config['first_tag_close'] = '</li>';
            $config['prev_link'] = '&laquo';
            $config['prev_tag_open'] = '<li class="prev">';
            $config['prev_tag_close'] = '</li>';
            $config['next_link'] = '&raquo';
            $config['next_tag_open'] = '<li>';
            $config['next_tag_close'] = '</li>';
            $config['last_tag_open'] = '<li>';
            $config['last_tag_close'] = '</li>';
            $config['cur_tag_open'] = '<li class="active"><a href="#">';
            $config['cur_tag_close'] = '</a></li>';
            $config['num_tag_open'] = '<li>';
            $config['num_tag_close'] = '</li>';
            $this->pagination->initialize($config);
            $data['page'] = ($this->uri->segment(2)) ? $this->uri->segment(2) : 0;
            $data['songList'] 
            = $this->metadata_model->fetch_metadata_record($arr,$config["per_page"], $data['page']);
            $data['pagination'] = $this->pagination->create_links();
            $this->load->view('pages/metadataview/metadata_search');
            $this->load->view('pages/metadataview/metadata_pagination',$data);
        }
    }   
}

我没有显示分页的第二页（接下来的2行），而是被重定向到以下视图：

$this->load->view('pages/metadataview/metadata_search');
$this->load->view('pages/metadataview/metadata_form');

连同消息："请至少提供一个输入！"

如何在浏览分页链接时跳过表单验证，同时在有人单击搜索按钮时使其工作？