我在错误登录时尝试将消息从PHP
-文件发送到twig
-文件时收到此错误:Notice: Undefined property: Twig_Environment::$render in
。我想显示来自mu PHP
的消息的同一页面-文件如下:
$twig = new Twig_Environment($loader);
echo $twig->render('register.twig');
if (isset($_POST['reg'])) {
if ($_POST['pwd1'] === $_POST['pwd2']) {
} else {
echo ("<script>location.href = $twig->render('register.twig', array('theMessage' => 'Wrong password!'));</script>");
exit;
}
}
并且在twig
-文件中:
{% if theMessage %}
{{ theMessage }}
{% endif %}
但它不起作用,我得到了上面的错误。我在设法解决它时遇到了很大的麻烦。我愿意接受任何建议或暗示。
问题是PHP正在消息中插入$twig
变量。最好更改此代码:
echo ("<script>location.href = $twig->render('register.twig', array('theMessage' => 'Wrong password!'));</script>");
对此:
echo sprintf("<script>location.href = %s;</script>", $twig->render('register.twig', array('theMessage' => 'Wrong password!')));