回显字符串/参数到数组 - php - echo string/parameter into array - php

echo string/parameter into array - php

本文关键字：数组 php 参数字符串 | 更新日期: 2024-06-29

从文件将键值插入到 php 中的关联数组时仍然存在问题。

<?
function RandomLine($filename) {
    $lines = file($filename);
    echo $lines[array_rand($lines)];
}
$a1 = RandomLine("p1.txt");
$a = array(
    1 => array(
        0 => "value1",
        1 => "value2",
        2 => "value3",
        3 => "value4",
        4 => "value5",
        7 => 4
    ),
    2 => array(
        0 => "value1a",
        1 => "value2a",
        2 => "value3a",
        3 => "value4a",
        4 => "value5a",
        7 => 4
    ),
    3 => array(
        //THE PROBLEM IS HERE, can't echo $a1 variable!
        echo $a1;
    ),
);
?>

文件 p1.txt 有两行：

0 => "value1",  1 => "value2",  2 => "value3",  3 => "value 4",  4 => "value5",  7 => 1
0 => "value6",  1 => "value7",  2 => "value8",  3 => "vealue9",  4 => "value10",  7 => 3

我收到错误：

Parse error: syntax error, unexpected T_ECHO, expecting ')'

有谁知道如何解决它？

您不会将值回显到数组中。

你只是这样使用它的名字

3 => array(
    1 => $a1,
  ...
  ...
)

删除最后一个数组后的逗号：

3 => array(
//THE PROBLEM IS HERE, can't echo $a1 variable!
echo $a1;
)

数组定义后移动回显：

3 => array(
  //THE PROBLEM IS HERE, can't echo $a1 variable!
  )
);
echo $a1;

如果你想从名为$a数组中回显一些东西，请执行以下操作：

echo $a[0];

这将只返回第一个数组，

所以如果你想从第一个数组中返回"value1"，请这样做：

echo $a[1][0];