PHP 语法字符串连接 - PHP syntax string join

PHP syntax string join

本文关键字：连接字符串语法 PHP | 更新日期: 2023-09-27

    $a = '
        SELECT * FROM `'. $table .'` WHERE `chrDate` > "'. $lastDate .'" INTO OUTFILE "'. $file .'"
        FIELDS TERMINATED BY ", " ENCLOSED BY ''"'' ESCAPED BY "'"
        LINES TERMINATED BY "'n"
';

我不知道为什么我不能这样做，我尝试解决它几次，但每次我都会给出这个错误:(

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''n"' at line 2

*回声$a *

SELECT * FROM `tbl_SaleApa` WHERE `chrDate` > "2001/03/29" INTO OUTFILE "C:/xampp/htdocs/transfer/tempfile/tbl_SaleApa.sql"
FIELDS TERMINATED BY ", " ENCLOSED BY '"' ESCAPED BY "'"
LINES TERMINATED BY "'n"

我有这个：编辑：您还将变量封装在不需要的双引号中。请参阅更新的代码。

<?php
$table='myTable';
$lastDate='myDate';
$file='myFile.ext';
$a = "SELECT * FROM $table WHERE chrDate > '$lastDate' INTO OUTFILE '$file' 
    FIELDS TERMINATED BY ', ' ENCLOSED BY ''"' ESCAPED BY '''' 
    LINES TERMINATED BY '''n'"; 
echo $a;
?>

输出以下内容：

SELECT * FROM myTable WHERE chrDate > 'myDate' INTO OUTFILE 'myFile.ext'
FIELDS TERMINATED BY ', ' ENCLOSED BY '"' ESCAPED BY ''' 
LINES TERMINATED BY ''n'

  $a = "SELECT * FROM " . $table . " WHERE chrDate > '" . $lastDate . "' INTO OUTFILE '" . $file . "' 
        FIELDS TERMINATED BY ', ' ENCLOSED BY ''"' ESCAPED BY '''' 
        LINES TERMINATED BY ''n'";

$sql = '
SELECT * FROM `'. $table .'` WHERE `chrDate` > "'. $lastDate .'" INTO OUTFILE "'. $file .'"
FIELDS TERMINATED BY ", " ENCLOSED BY ''"'' ESCAPED BY "''"
LINES TERMINATED BY "'n"';

我的问题解决了：

$a = '
SELECT * FROM `'. $table .'` WHERE `chrDate` > "'. $lastDate .'" INTO OUTFILE "'. $file .'"
FIELDS TERMINATED BY ", " ENCLOSED BY ''"'' ESCAPED BY "'''"
LINES TERMINATED BY "'n"
';

将ESCAPED BY "'"更改为ESCAPED BY "'''"