PHP cURL 如何获取图像宽度


PHP cURL How to get image width?

这是我到目前为止尝试过的:

$h = curl_init();
$headers = array(
"Range: bytes=0-700"
);
curl_setopt($h, CURLOPT_URL, $url);
curl_setopt($h, CURLOPT_HTTPHEADER, $headers);
curl_setopt($h, CURLOPT_RETURNTRANSFER, 1); //return the image value
$mh = curl_multi_init();
curl_multi_add_handle($mh, $h);
$running = null;
do {
   curl_multi_exec($mh, $running);
} while ($running > 0);
$raw = curl_multi_getcontent($h);
$im = imagecreatefromstring($raw);

 $width = imagesx($im);
    $height = imagesy($im);

var_dump($width);

每当我运行代码时,我都会收到此错误:

> ( ! ) Warning: imagecreatefromstring(): Data is not in a recognized
> format in
> C:'wamp'www'......funcs.php on
> line 399 Call Stack
> # Time    Memory  Function    Location 1  0.0022  294120  {main}( )   ..'...

如果你var_dump( $raw )它说:

string '<html>
<head><title>302 Found</title></head>
<body bgcolor="white">
<center><h1>302 Found</h1></center>
<hr><center>BSWS/2.1</center>
</body>
</html>
' (length=157)

可能是什么问题...我已经花了 6 个多小时试图解决这个问题......请帮忙。谢谢

看起来您正在接收来自服务器的重定向,并且 cURL 将其作为内容而不是图像本身。 尝试使用CURLOPT_FOLLOWLOCATION选项。

所以:

curl_setopt($h, CURLOPT_URL, $url);
curl_setopt($h, CURLOPT_HTTPHEADER, $headers);
curl_setopt($h, CURLOPT_RETURNTRANSFER, 1); //return the image value

成为:

curl_setopt($h, CURLOPT_URL, $url);
curl_setopt($h, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($h, CURLOPT_HTTPHEADER, $headers);
curl_setopt($h, CURLOPT_RETURNTRANSFER, 1); //return the image value

cURL 的完整选项列表如下: http://php.net/manual/en/function.curl-setopt.php