无法从安卓中的 php 获取 Json


Not able to get Json from php in android?

我得到这个日志猫:

08-14 11:42:55.923: W/System.err(1137): org.json.JSONException: Value {"error":0,"success":0,"tag":"helloworld"} of type org.json.JSONObject cannot be converted to JSONArray

如何解决此问题?

08-14 11:42:55.923: W/System.err(1137):     at org.json.JSON.typeMismatch(JSON.java:111)

我使用的代码是:

public class MainActivity extends Activity {
    TextView tv;
    HttpClient client;
    JSONObject json;
final static String URL = "http://192.168.1.9/sumit/hello.php";
    //final static String URL = "http://json.org/example.html";
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        tv = (TextView) findViewById(R.id.tv1);
        client = new DefaultHttpClient();
        Log.e("my","check");
        new Read().execute("tag");
//      StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder()
//              .detectAll().penaltyLog().build();
//      StrictMode.setThreadPolicy(policy);
    }
    public JSONObject myData() throws ClientProtocolException, IOException,
            JSONException {
        StringBuilder url = new StringBuilder(URL);
        HttpGet get = new HttpGet(url.toString());
        HttpResponse r = client.execute(get);
        int status = r.getStatusLine().getStatusCode();
        if (status == 200) {
            HttpEntity e = r.getEntity();
            String data = EntityUtils.toString(e);
            JSONArray datastream = new JSONArray(data);
            JSONObject message = datastream.getJSONObject(0);
            return message;
        } else {
            Toast.makeText(MainActivity.this, "error encountered",
                    Toast.LENGTH_SHORT).show();
            return null;
        }
    }
    class Read extends AsyncTask<String, Integer, String> {
        @Override
        protected String doInBackground(String... params) {
            // TODO Auto-generated method stub
            try {
                json = myData();
                                    return json.getString(params[0]);

            } catch (ClientProtocolException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return null;
        }
        @Override
        protected void onPostExecute(String result) {
            // TODO Auto-generated method stub
            tv.setText(result);
        }
    }
}

生成的 JSON 代码:

{"tag":"hello","success":0,"error":0}

用于生成以下内容的代码:

<?php

    // response Array
    $response = array("tag" => helloworld, "success" => 0, "error" => 0);

   echo json_encode($response);

?>

因为你得到的不是JSONArray - 它是JSONObject

JSONArray 在你的例子中看起来像这样:

[{"error":0,"success":0,"tag":"helloworld"}]

它是一个带有一个元素的数组(即 JSONObject ,其中包含字段)。

我不太了解 php(我也不知道json_encode是如何工作的),但试试这个:

<?
    $response = array(array("tag" => helloworld, "success" => 0, "error" => 0));
    echo json_encode($response);
?>