如何从数组中提取和删除选定的变量


How to extract and remove selected variables from an array?

我有以下数组:

$var_array = array(
 "length"  => 5,
 "breadth"  => 5,
 "color" => "blue",
 "size"  => "medium",
 "shape" => "square");

如何通过指定键从数组中提取选定的变量?

例如,如果我指定breadthsize,我会得到:

$breadth = 5;
$size = "medium";
$var_array = array(
 "length"  => 5,
 "color" => "blue",
 "shape" => "square");

array_diff_keyarray_intersect_key

$array  = array(
  'breadth' => 1, 
  'size' => 2, 
  'length' => 3,
  'colour' => 4,
  'shape' => 5
);
$keys      = array('breadth', 'size');
$new_array = array_intersect_key($array, array_flip($keys));
$array     = array_diff_key($array, $new_array);

将产生:

// $new_array
array(2) {
 ["breadth"] => int(1)
 ["size"]    => int(2)
}
// $array
array(3) {
 ["length"] => int(3)
 ["colour"] => int(4)
 ["shape"]  => int(5)
}

如果你想把它们放到局部变量中,你可以这样做:

list($length, $colour, $shape) = array_values($new_array);

或者不太清楚的版本:

extract($new_array);

解决方案:

$keys = array('breadth', 'size');  // which keys do you want to extract?
foreach($keys as $key) {
    $newArr[$key] = $var_array[$key];  // put'em in newArr
    unset($var_array[$key]);
}
extract($newArr);   // extract them to convert keys to variables
unset($newArr);   // unset newArr

Goldenparrot 已经提供了一个很好的答案,但如果你想要一个不使用 foreach 的解决方案,你可以改用array_intersect_key:

$var_array = array(...)
$keysToExtract = array('breadth', 'size');
extract(array_intersect_key($var_array, array_fill_keys($keysToExtract, true));

试试这个

$var_array = array(
 "length"  => 5,
 "breadth"  => 5,
 "color" => "blue",
 "size"  => "medium",
 "shape" => "square");

reset($var_array);
$myarray =array();

while (list($key, $val) = each($var_array))
{
  if($key!='length' && $key!='size' )
  {
    $myarray[$key] =  $val;
  }else{
   echo "$key => $val<br />";
 }

}

输出

size=> medium
breadth => 5
Array
(
    [color] => blue
    [length] => 5
    [shape] => square
)