给定了PHP preg_replace字符串路径


PHP preg_replace string path given

我在PHP中的preg_replace函数有问题。我想不出图案和替代品。

我有两个字符串和一些代码:

    $dirname1 = 'hdadas/dasdad/dasd/period_1min';
    $dirname2 = 'hdadas/dasdad/dasd/period_1min/abcdrfg.php';
    $pieces1 = explode('/', $dirname1);
    $pieces2 = explode('/', $dirname2);
    $dirname1 = end($pieces1);  // output will be period_1min
    $dirname2 = end($pieces2); // output will be abcdrfg.php
    $output = preg_replace($pattern, $replacement, $dirname1); // or (..,..,$dirname2
    echo $output; // i need 1min(without period_) or abcdrfg (without .php)

UPD:

   function Cat($dirname)
   {
      $name = explode('/', $dirname);
      $pattern = ???;
      $replacement = ???;
      return preg_replace($pattern, $replacement, $dirname1);
    }
    print(Cat('hdadas/dasdad/dasd/period_1min'))); // output need 1min only
    print(Cat('hdadas/dasdad/dasd/period_1min/abcdrfg.php'))); // output  need abcdrfg only  

这应该适用于您:

(这里我用basename()只得到路径的最后一部分,然后用pathinfo()得到没有扩展名的最后一个部分。之后我只用preg_replace()用空字符串替换下划线之前的所有内容)

<?php
    $dirname1 = "hdadas/dasdad/dasd/period_1min";
    $dirname2 = "hdadas/dasdad/dasd/period_1min/abcdrfg.php";
    $dirname1 = pathinfo(basename($dirname1))["filename"];
    $dirname2 = pathinfo(basename($dirname2))["filename"];
    echo $output = preg_replace("/(.*)_/", "", $dirname1); 

?>

输出:

1min
abcdrfg

这个正则表达式/^.+_|'.[^.]+$/:怎么样

$dirname1 = 'hdadas/dasdad/dasd/period_1min';
$dirname2 = 'hdadas/dasdad/dasd/period_1min/abcdrfg.php';
$pieces1 = explode('/', $dirname1);
$pieces2 = explode('/', $dirname2);
$dirname1 = end($pieces1);  // output will be period_1min
$dirname2 = end($pieces2); // output will be abcdrfg.php
$output = preg_replace('/^.+_|'.[^.]+$/', '', $dirname1); // or (..,..,$dirname2
echo $output,"'n"; // i need 1min(without period_) or abcdrfg (without .php)
$output = preg_replace('/^.+_|'.[^.]+$/', '', $dirname2); // or (..,..,$dirname2
echo $output,"'n"; // i need 1min(without period_) or abcdrfg (without .php)

输出:

1min
abcdrfg