PHP返回无效请求错误 - PHP returns Invalid Request Error

PHP returns Invalid Request Error

本文关键字：错误请求无效返回 PHP | 更新日期: 2023-09-27

我正在将数据从Android设备保存到MySQL。我的代码使用Localhost运行良好，但当我尝试使用托管域时。它给了我错误。

返回错误

ERROR
The requested URL could not be retrieved
While trying to process the request:
POST /insert.php HTTP/1.1
Transfer-Encoding: chunked
Content-Type: application/x-www-form-urlencoded
Host: mydomain.com
Connection: Keep-Alive
User-Agent: Apache-HttpClient/UNAVAILABLE (java 1.4)
The following error was encountered:
Invalid Request

AsyncTask内的Java代码

.
.
.
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("user_id", userId));
HttpPost httppost = new HttpPost("http://mydomain.com/insert.php");
HttpClient httpclient = new DefaultHttpClient();
UrlEncodedFormEntity urlEncodeFormEntity = new UrlEncodedFormEntity(nameValuePairs);
urlEncodeFormEntity.setChunked(true);
httppost.setEntity(urlEncodeFormEntity);
HttpResponse response = httpclient.execute(httppost);
.
.
.

请帮我解决这个问题。它再次使用Localhost工作。

编辑：

PHP代码：这只是为了测试我的设备是否可以访问给定的URL

<?php
    echo "Ive been reached.";
    //Codes to connect DB and To Insert goes here
?>

尝试此代码

 HttpClient httpclient = new DefaultHttpClient();
 HttpPost httppost = new HttpPost("http://exampple.com/insert-data.php");
 List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
 nameValuePairs.add(new BasicNameValuePair("id", "1"));
 try{
  httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
  ResponseHandler<String> responseHandler = new BasicResponseHandler();
  String response = httpclient.execute(httppost, responseHandler);
  String reverseString = response;
  Log.d("Mishu Complain",reverseString);
 } catch(Exception e){ // check error here  }

要在日志中找到任何错误，您可以将此代码放入

catch (Exception anyError) {
             Log.e("Mishu-Cn-Error", "exception",anyError);
        }

我通过删除行解决了这个问题

urlEncodeFormEntity.setChunked(true);