php str_word_count到c#的端口

好吧，这是我的"糟糕的C#"示例（在混合返回类型中模仿PHP）。这是一个利用.NET正则表达式的相当琐碎的实现。

private enum WORD_FORMAT
{
    NUMBER = 0,
    ARRAY = 1,
    ASSOC = 2
};
private static object str_word_count(string str, WORD_FORMAT format, string charlist)
{
    string wordchars = string.Format("{0}{1}", "a-z", Regex.Escape(charlist));
    var words = Regex.Matches(str, string.Format("[{0}]+(?:[{0}'''-]+[{0}])?", wordchars), RegexOptions.Compiled | RegexOptions.IgnoreCase);
    if (format == WORD_FORMAT.ASSOC)
    {
        var assoc = new Dictionary<int, string>(words.Count);
        foreach (Match m in words)
            assoc.Add(m.Index, m.Value);
        return assoc;
    }
    else if (format == WORD_FORMAT.ARRAY)
    {
        return words.Cast<Match>().Select(m => m.Value).ToArray();
    }
    else // default to number.
    {
        return words.Count;
    }
}

因此，如果您选择ASSOC，函数将返回一个Dictionary<int,string>，如果选择ARRAY，则返回一个string[]，如果选择NUMBER，则返回简单的int。

一个例子（我在这里复制了PHP的例子

static void Main(string[] args)
{
    string sentence = @"Hello fri3nd, you're
   looking          good today!";
    var assoc = (Dictionary<int,string>)str_word_count(sentence, WORD_FORMAT.ASSOC, string.Empty);
    var array = (string[])str_word_count(sentence, WORD_FORMAT.ARRAY, string.Empty);
    var number = (int)str_word_count(sentence, WORD_FORMAT.NUMBER, string.Empty);
    //test the plain array
    Console.WriteLine("Array'n(");
    for (int i = 0; i < array.Length; i++)
        Console.WriteLine("'t[{0}] => {1}", i, array[i]);
    Console.WriteLine(")");
    // test the associative
    Console.WriteLine("Array'n(");
    foreach (var kvp in assoc)
        Console.WriteLine("'t[{0}] => {1}", kvp.Key, kvp.Value);
    Console.WriteLine(")");
    //test the charlist:
    array = (string[])str_word_count(sentence, WORD_FORMAT.ARRAY, "àáãç3");
    Console.WriteLine("Array'n(");
    for (int i = 0; i < array.Length; i++)
        Console.WriteLine("'t[{0}] => {1}", i, array[i]);
    Console.WriteLine(")");
    //test the number
    Console.WriteLine("'n{0}", number);
    Console.Read();
}

但是，我想在这里补充一点：不要返回对象。它可以与PHP一起使用aok，因为它不是一种强类型语言。实际上，您应该编写函数的各个版本，以满足每种不同的格式。无论如何，这应该会让你开始：）

输出：

Array
(
    [0] => Hello
    [1] => fri
    [2] => nd
    [3] => you're
    [4] => looking
    [5] => good
    [6] => today
)
Array
(
    [0] => Hello
    [6] => fri
    [10] => nd
    [14] => you're
    [25] => looking
    [42] => good
    [47] => today
)
Array
(
    [0] => Hello
    [1] => fri3nd
    [2] => you're
    [3] => looking
    [4] => good
    [5] => today
)
7