Php无法检索动态生成的文本字段

我无法检索使用javascript创建的动态生成的文本字段和单选按钮，但可以检索使用html手动添加到表单中的文本字段。

以前，我使用样式来隐藏和显示我的所有文本字段，而不是动态创建的文本字段，所以我获取所有文本字段没有问题，并且可以放心地假设我的PHP处理没有任何问题。

我的HTML/接口编码

<?php
for ($x = 1; $x <= 5; $x++)
{
    $inputAreaID = "inputArea".$x;// Creating all dynamic options and etc in this div using javascript 
    $typeID = "type".$x; //for select type id
    $opt2ID = "answers".$x; 
    $optID = "opt".$x; 
    $comID = "com".$x; 
    $qnName = "qn".$x // for qn textfield name?>
<table>
    <tr>
        <td>Question <?php echo $x ?></td>
        <td><input type="text" name='<?php echo $qnName ?>' required></td>
    </tr>
    <tr>
        <td>Question Type</td>
        <td>
        <select id="<?php echo $typeID ?>" name="<?php echo $typeID ?>" onclick="showQuestionSelect('<?php echo $x ?>', '<?php echo $typeID ?>', '<?php echo $inputAreaID ?>')">
        <option value="">Please select one option </option>                 
            <option value="Yes,No">Yes/No </option>
            <option value="True,False">True/False</option>
            <option value="3">A. B. C. D.</option>
        </select>
        </td>
    </tr>
 </table>   
        <div id='<?php echo $inputAreaID ?>' style="margin-bottom: 1px;margin-top:1px;"></div>

JavaScript编码

function showQuestionSelect(questionNo, typeID, inputArea) 
{
var s = String(typeID);
var i = String(inputArea);
var e = document.getElementById(s);
var selectedOpt = e.options[e.selectedIndex].value;
ansID = questionNo + "_ans";
comID = questionNo + "_com";
optA = questionNo + "_optA";
optB = questionNo + "_optB";
optC = questionNo + "_optC";
optD = questionNo + "_optD";
var msg = "";

if (selectedOpt == "True,False")
{
    msg ="<div style='margin-bottom: 10px;margin-top:10px;'><input type='radio' name='"+ ansID + "' value='True'> Submit True as Answer<input type='radio' name='" +ansID +"' value='False'> Submit False as Answer</div>";     
    msg +="<div style='margin-bottom: 10px;margin-top:10px;'>Reason for the answer: <input type='text' name='" + comID + "' value='' /></div>"
}
else if (selectedOpt == 3)
{
    msg = "<div style='margin-bottom: 10px;margin-top:10px;'>";
    msg += "Option A: <input type='text' name='" + optA + "' value='' /> <input type='radio' name='" + ansID + "' value='" + optA + "'> Submit as Answer  <br><br>";
    msg += "Option B: <input type='text' name='" + optB + "' value='' /> <input type='radio' name='" + ansID + "' value='" + optB + "'> Submit as Answer  <br><br>";
    msg += "Option C: <input type='text' name='" + optC + "' value='' /> <input type='radio' name='" + ansID + "' value='" + optC + "'> Submit as Answer  <br><br>";
    msg += "Option D: <input type='text' name='" + optD + "' value='' /> <input type='radio' name='" + ansID + "' value='" + optD + "'> Submit as Answer  </div>";      
    msg +="<div style='margin-bottom: 10px;'>Reason for the answer: <input type='text' name='" + comID + "' value='' /></div>";
}
document.getElementById(i).innerHTML = msg;
}

PHP处理编码

for ($x = 1; $x <= 5; $x++)
{
    $qn = $_POST["qn".$x]; // for qn textfield name
    $type = $_POST["type".$x]; //for select type id
    $ans = $_POST[$x."_ans"]; //for answer div id
    $reason = $_POST[$x."_com"]; //for answer div id
    $optionType = "";//to put into database
    if ($type == "Yes,No")
    {
        $ans = "";
        $reason = "";
    }
    if ($type == "3")
    {
        $optA = $_POST[$x."_optA"];
        $optB = $_POST[$x."_optB"];
        $optC = $_POST[$x."_optC"];
        $optD = $_POST[$x."_optD"];
        $optionType = $optA.",".$optB.",".$optC.",".$optD;
        if ($ans == $x."_optA")
            $ans = $optA;
        else if ($ans == $x."_optB")
            $ans = $optB;
        else if ($ans == $x."_optC")
        $ans = $optC;
        else 
            $ans = $optD;
    }
    else
        $optionType = $type;

有人能帮忙吗？