我正试图从查询中获取变量，并使用以下查询将其存储为cookie：
$query="SELECT id,username,password FROM employee where email='$email' AND password='$password' Limit 1";
$result= $mysqli->query($query);
if($result->num_rows == 1){
$stmt = $mysqli->prepare($query);
$stmt->execute();
$stmt->store_result();
$stmt->bind_result($user_id, $username, $db_password);
$user_browser = $_SERVER['HTTP_USER_AGENT'];
$_SESSION['user_id'] = $user_id;
//used echo to check stored variables
echo "user_id=".$_SESSION['user_id'];
//used echo here to check the query result
$_SESSION['username'] = $username;
echo "username=".$username;
$_SESSION['login_string'] = hash('sha512',
$password . $user_browser);
// Login successful.
return true;
}
else{
// Password is not correct
// We record this attempt in the database
$now = time();
$mysqli->query("INSERT INTO login_attempts(user_id, time)
VALUES ('$user_id', '$now')");
return false;
}
}
我在网站上看到的是：user_id=0username=
这就是我解决问题的方法：
$quer="SELECT id,username FROM employee where email=?";
if($result->num_rows == 1){
$stmt = $mysqli->prepare($quer);
$stmt->bind_param('i',$email);
$stmt->execute();
$stmt->bind_result($user_id,$username);
添加：
while($stmt->fetch()) {}
用于：
echo "Cookies username:".$_SESSION['username']." ";
echo "db username".$username;
得到的结果：
Cookies username:test_user db usernametest_user
谢谢你们的帮助。