如何编辑代码点火器窗体下拉列表


How to edit codeigniter form drop down

我正在使用codeigniter表单下拉列表。

add_store.php代码如下:-

 <tr>
            <td>country</td>
            <td><?=form_input('country', set_value('country'));?></td>
            <td class="error"><?php echo form_error('country'); ?></td>
        </tr>
    <tr>
        <td><?=form_dropdown('Equipment',$options = array(
                                '1'   => '1',
                                '2'   => '2',
                                '3'   => '3',
                                '4'   => '4',
                                '5'   => '5',
                                '6'   => '6',
                                '7'   => '7',
                                '8'   => '8',
                                '9'   => '9',
                                '10' => '10'));?></td>
    </tr>

我将此表单添加到数据库中,它运行良好。

现在我想编辑这个页面。我正在做这样的事情:-

edit_store.php页面在这里

<tr>
                <td>country</td>
                <td><?=form_input('country', set_value('country', $store['country']));?></td>
                <td class="error"><?php echo form_error('country'); ?></td>
</tr>
 <tr>
                <td>Equipment Rating</td>
                <td><?=
                                $selected_Equipment = $this->input->post('Equipment');
                                form_dropdown('Equipment'$selected_Equipment);?></td>
    // what i can do here, I am doing something wrong here??????????????????????????????????????????            
</tr>

我的问题是:对于来自数据库的所选下拉列表,我能做什么?

如何编辑下拉选择的值?

那我该怎么办???

    <?php
    $selected_Equipment = '1';
    $options = array(
                     '1'   => '1',
                     '2'   => '2',
                     '3'   => '3',
                     '4'   => '4',
                     '5'   => '5',
                     '6'   => '6',
                     '7'   => '7',
                     '8'   => '8',
                     '9'   => '9',
                     '10' => '10');
   form_dropdown('Equipment',$options,$selected_Equipment);
   ?>

希望这能有所帮助!

Kugutsumen是对的,form_dropdown函数的语法有点错误。你可以在这里看到它所包含的论点:http://codeigniter.com/user_guide/helpers/form_helper.html