我有三个.php
文件。
db_conx.php
$db_conx = mysqli_connect("localhost", "admin", "admin", "gestiune");
// Evaluate the connection
if (mysqli_connect_errno()) {
echo mysqli_connect_error();
exit();
}
functions.php
function deplata($pid){
$sqlp = "SELECT * FROM plati WHERE user_id";
$queryp = mysqli_query($db_conx, $sqlp);
$type = "day";
$payments = 0;
$salary = 80;
$days = 4;
$topay = 0;
while($getplata = mysqli_fetch_assoc($queryp)){
$plati += $getplata['valoare'];
}
if($tip == "day"){
$topay = $days * $salary;
}
return $topay;
}
我有一个index.php文件来调用这些文件并使用它们。
include_once("php_includes/db_conx.php");
include_once("php_includes/functii.php");
$salariu = deplata(5);
echo $salariu;
问题是它不会连接到数据库,并返回一些错误:
注意:未定义的变量:中的db_conxD: 第5行上的''examplep''htdocs''manager''pages''php_includes''functions.php
警告:mysqli_query()要求参数1为mysqli,给定null在第5行上的D:''examplep''htdocs''manager''pages''php_includes''functions.php中
警告:mysqli_fetch_assoc()要求参数1为mysqli_result,D:''examplep''htdocs''manager''pages''php_includes''functions.php中给定null在线11
然后它打印值(因为它当前不使用数据库中的任何值)。我尝试的内容:我尝试将functions.php
内容直接放入index.php
文件中,我尝试在functions.php
文件中调用db_conx.php
文件。
您需要在function.php
中定义值。请检查以下代码
function.php
function deplata($pid){
global $db_conx;
$sqlp = "SELECT * FROM plati WHERE user_id";
$queryp = mysqli_query($db_conx, $sqlp);
$type = "day";
$payments = 0;
$salary = 80;
$days = 4;
$topay = 0;
while($getplata = mysqli_fetch_assoc($queryp)){
$plati += $getplata['valoare'];
}
if($tip == "day"){
$topay = $days * $salary;
}
return $topay;
}
index.php
检查index.php
中的拼写错误
include_once("php_includes/function.php");