我似乎不明白pjax为什么在第二次提交表单时重新加载页面。它在从该url /site/profile?UserSearch%5Bsearchstring%5D=mi&_pjax=%23form-pjax提取的第一个表单提交中完全按照预期工作，但是，在第一个表单之后，它失去了url /site/profile?UserSearch%5Bsearchstring%5D=m的结尾。我检查了实际的html代码，表单保留了data-ajax属性。当pjax重新加载整个页面时，我尝试增加超时时间，但这并没有改变任何事情。
以下是我的视图中的代码
<?php Pjax::begin(['timeout' => 5000, 'id' => 'form-pjax']); ?>
<?php $form = ActiveForm::begin([
'method' => 'get',
'action' => Url::to(['site/profile']),
'options' => ['data-pjax' => true ],
]); ?>
<?= $form->field($searchModel, 'searchstring', [
'template' => '<div class="input-group">{input}<span class="input-group-btn">' .
Html::submitButton('Search', ['class' => 'btn btn-default']) .
'</span></div>',
])->textInput(['placeholder' => 'Find friends by username or email']);
?>
<?php ActiveForm::end(); ?>
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
'username',
[
'label' => 'View Profile',
'format' => 'raw',
'value'=>function ($data) {
return Html::a(Html::encode("View Profile"),'/site/redirectprofile/'.$data->id);
},
],
[
'label' => 'Follow',
'format' => 'raw',
'value'=>function ($data) {
return Html::a(Html::encode(Follow::find()->where(['user_id' => $data->id, 'follower_id' => Yii::$app->user->Id])->exists() ? 'Unfollow' : 'Follow'),'/site/follow/'.$data->id.'/'.$data->username);
},
],
],
'summary'=>'',
]); ?>
<?php Pjax::end(); ?>
每次重新加载pjax后，必须调用所需的javascript触发器/函数，如：
$('#form-pjax').on('pjax:success', function() {
/*call Your functions here, or copy from your generated page js code,
that bind event to pjax form,
at end of generated html You should have something like: */
jQuery(document).on('submit', "#form-pjax form[data-pjax]", function (event) {
jQuery.pjax.submit(event, '#form-pjax', {"push":true,"replace":false,"timeout":000,"scrollTo":false});
});
});
这不是yii2的问题，而是javascript的工作方式，当您动态添加内容时，需要为每个添加的元素绑定触发器/事件。