我试图用PHP的array_combine()函数组合两个数组，但我收到了以下错误：
array_combine（）要求参数1为数组，字符串给定
$subjects的var_dump显示如下：
array(
(int) 0 => 'English',
(int) 1 => 'Mathematics',
(int) 2 => 'Biology',
(int) 3 => 'Physics',
(int) 4 => 'Chemistry'
)
$custom的var_dump显示如下：
array(
(int) 0 => array(
'score' => '72',
'grade' => 'B+',
'points' => '10'
),
(int) 1 => array(
'score' => '99',
'grade' => 'A',
'points' => '12'
),
(int) 2 => array(
'score' => '77',
'grade' => 'A-',
'points' => '11'
),
(int) 3 => array(
'score' => '50',
'grade' => 'C+',
'points' => '7'
),
(int) 4 => array(
'score' => '66',
'grade' => 'B+',
'points' => '10'
)
)
功能：
function score($received,$arr) {
$keys = $received;
$data_set = array_combine($keys,$arr);
return $data_set;
}
这里是我调用函数的地方：
$data_set = array_map(array($this->Scores,'score'),$subjects ,custom);
如果调试将所有变量显示为数组：为什么$subjects显示为array_component的字符串？
编辑：
预期输出
array(
'English' => array(
'score' => '72',
'grade' => 'B+',
'points' => '10'
),
'Mathematics' => array(
'score' => '99',
'grade' => 'A',
'points' => '12'
),
'Biology' => array(
'score' => '77',
'grade' => 'A-',
'points' => '11'
),
'Physica' => array(
'score' => '50',
'grade' => 'C+',
'points' => '7'
),
'Chemistry' => array(
'score' => '66',
'grade' => 'B+',
'points' => '10'
)
)
当您用预期输出更新问题时，您不需要array_map()。只需这样做：
$data_set = array_combine($subjects, $custom);
否则，您所做的就是循环遍历$subjects和$custom的所有元素。
所以你每次迭代都是这样做的：
return array_combine("English", ["score" => "72", "grade" => "B+", "points" => "10"]);
return array_combine("Mathematics", ["score" => "99", "grade" => "A", "points" => "12"]);
//...
简单地尝试一下，不需要额外的array_map
$data_set = array_combine($subjects, $custom);