情况是我有两个数组通过API收集JSON数据：
$players = getAPI("http://xx.xxx.xxx.xx:xxxxx/players.json?apiKey=xxxxxxxxxxxxxxxxxxxxxxxx");
$recents = getAPI("xx.xxx.xxx.xx:xxxxx/recent.json?apiKey=xxxxxxxxxxxxxxxxxxxxxxxx");
方法是获取内容并将JSON解码为数组。对于玩家阵列，我们在一个阵列中有以下数据：
$players
[
{
"id": "76561198033377272",
"name": "PitMonk",
"position": {
"x": -339,
"y": 26,
"z": 191
},
"rotation": 128,
"time": 418310,
"ip": "",
"inventory": {
"main": [],
"belt": [
{
"name": "rock",
"amount": 1,
"blueprint": false,
"condition": 100
},
{
"name": "torch",
"amount": 1,
"blueprint": false,
"condition": 100
}
],
"wear": []
}
},
{
"id": "76561198088638439",
"name": "Pippa",
"position": {
"x": -337,
"y": 25,
"z": 177
},
"rotation": 73,
"time": 419136,
"ip": "",
"inventory": {
"main": [
{
"name": "arrow.wooden",
"amount": 12,
"blueprint": false
},
{
"name": "bow.hunting",
"amount": 1,
"blueprint": false,
"condition": 93
},
{
"name": "blueprint_fragment",
"amount": 25,
"blueprint": false
},
{
"name": "metal.fragments",
"amount": 1366,
"blueprint": false
},
{
"name": "metal.refined",
"amount": 48,
"blueprint": false
},
{
"name": "charcoal",
"amount": 1120,
"blueprint": false
},
{
"name": "lowgradefuel",
"amount": 738,
"blueprint": false
}
],
"belt": [
{
"name": "rock",
"amount": 1,
"blueprint": false,
"condition": 100
},
{
"name": "torch",
"amount": 1,
"blueprint": false,
"condition": 100
},
{
"name": "pickaxe",
"amount": 1,
"blueprint": false,
"condition": 76
},
{
"name": "pickaxe",
"amount": 1,
"blueprint": false,
"condition": 17
},
{
"name": "pickaxe",
"amount": 1,
"blueprint": false,
"condition": 100
},
{
"name": "pickaxe",
"amount": 1,
"blueprint": false,
"condition": 100
}
],
"wear": [
{
"name": "burlap.shirt",
"amount": 1,
"blueprint": false
},
{
"name": "attire.hide.skirt",
"amount": 1,
"blueprint": false
}
]
}
}
]
$recents
[
{
"id": "76561198039206786",
"name": "JakeGroves"
},
{
"id": "76561198088638439",
"name": "Pippa"
},
{
"id": "76561198033377272",
"name": "PitMonk"
},
{
"id": "76561198146864439",
"name": "YepWellDone"
},
{
"id": "76561198164836207",
"name": "Baz"
},
{
"id": "76561198076406281",
"name": "xwalnutx"
},
{
"id": "76561197985716090",
"name": "Darkflame134"
},
{
"id": "76561198263423842",
"name": "XitaikiznerX"
},
{
"id": "76561198129952244",
"name": "NatanGamer"
},
{
"id": "76561198071842055",
"name": "Baha Bey"
}
]
正如你所看到的，玩家是连接的人，最近的是最近连接的人的总列表。
我尝试过：
foreach ($players as $player) {
echo $players->name;
}
echo "</br></br>";
foreach ($recent as $rec) {
if ($rec->name != $player->name) {
echo $rec->name . "</br>";
}
}
它产生的结果是：
PitMonk Pippa
JakeGroves
PitMonk
YepWellDone
Baz
xwalnutx
Darkflame134
XitaikiznerX
NatanGamer
Baha Bey
所以它只是忽略了"pippa"，我不确定是否可以像这样与两个数组交互以获得唯一值？
您有兴趣列出$users中不存在于$players或$recents中的所有名称，对吗？
假设你只对这个名字感兴趣：
// First, let's get a new array with all names from both arrays (can contain dups)
$pcNames = array_map($players + $recents, function($playerObject) {
return $playerObject->name;
});
// Next, let's remove all dups
$pcNames = array_unique($pcNames);
// === At this point you have an array with all names from `$players` and `$recents` ===
// === You may do something else with those, but I'll now create another array with ===
// === all users not in the players/recents lists. ===
// Now let's also get a list of names of users in the `$users` variable
$userNames = array_map($users, function($playerObject) {
return $playerObject->name;
});
// And finally let's get all names which are not in players or recents
$diffNames = array_diff($userNames, $pcNames);
// Let's output those to see whether it worked
var_dump($diffNames);
当然，根据您的用例，还有其他方法。例如，我们可以提取所有三个数组的名称，然后只使用带有3个参数的array_diff（但您没有$pcArray的副产品），或者如果您真的想比较ID但打印名称，我们必须更改所有内联函数以提取ID而不是名称，并进一步向下引用用户数组以获得实际名称，等等。