我可以在jQuery数组中回显php吗


Can I Echo php inside jQuery Array?

我正在做一个项目,似乎不知道处理这个问题的最佳方法。我正在使用jQuery Supersized和options框架来构建一个主题。除了图像之外,我已经为滑块选项做了所有的工作。这是我的脚本

<script type="text/javascript">
    jQuery(function ($) {
        $.supersized({
            // Functionality
            slideshow: 1, // Slideshow on/off
            autoplay: <? php echo of_get_option('autoplay', '1'); ?> , // Slideshow starts playing automatically
            start_slide: 1, // Start slide (0 is random)
            stop_loop: 0, // Pauses slideshow on last slide
            random: <? php echo of_get_option('random', '0'); ?> , // Randomize slide order (Ignores start slide)
            slide_interval: <? php echo of_get_option('slide_interval', '3000'); ?> , // Length between transitions
            transition: <? php echo of_get_option('transitions', '1'); ?> , // 0-None, 1-Fade, 2-Slide Top, 3-Slide Right, 4-Slide Bottom, 5-Slide Left, 6-Carousel Right, 7-Carousel Left
            transition_speed: 1000, // Speed of transition
            new_window: 1, // Image links open in new window/tab
            pause_hover: 0, // Pause slideshow on hover
            keyboard_nav: 1, // Keyboard navigation on/off
            performance: 1, // 0-Normal, 1-Hybrid speed/quality, 2-Optimizes image quality, 3-Optimizes transition speed // (Only works for Firefox/IE, not Webkit)
            image_protect: <? php echo of_get_option('protect_images', '1'); ?> , // Disables image dragging and right click with Javascript
            // Size & Position                         
            min_width: 0, // Min width allowed (in pixels)
            min_height: 0, // Min height allowed (in pixels)
            vertical_center: 1, // Vertically center background
            horizontal_center: <? php echo of_get_option('horizontal_center', '1'); ?> , // Horizontally center background
            fit_always: <? php echo of_get_option('always_fit', '0'); ?> , // Image will never exceed browser width or height (Ignores min. dimensions)
            fit_portrait: 1, // Portrait images will not exceed browser height
            fit_landscape: 0, // Landscape images will not exceed browser width
            // Components                           
            slide_links: 'blank', // Individual links for each slide (Options: false, 'num', 'name', 'blank')
            thumb_links: 1, // Individual thumb links for each slide
            thumbnail_navigation: 0, // Thumbnail navigation
            slides: [ // Slideshow Images
            {
                image: '<?php echo of_get_option("image_1"); ?>'
            }, {
                image: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/slides/kazvan-2.jpg',
                title: 'Image Credit: Maria Kazvan',
                thumb: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/thumbs/kazvan-2.jpg',
                url: 'http://www.nonsensesociety.com/2011/04/maria-kazvan/'
            }, {
                image: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/slides/kazvan-3.jpg',
                title: 'Image Credit: Maria Kazvan',
                thumb: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/thumbs/kazvan-3.jpg',
                url: 'http://www.nonsensesociety.com/2011/04/maria-kazvan/'
            }, {
                image: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/slides/wojno-1.jpg',
                title: 'Image Credit: Colin Wojno',
                thumb: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/thumbs/wojno-1.jpg',
                url: 'http://www.nonsensesociety.com/2011/03/colin/'
            }, {
                image: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/slides/wojno-2.jpg',
                title: 'Image Credit: Colin Wojno',
                thumb: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/thumbs/wojno-2.jpg',
                url: 'http://www.nonsensesociety.com/2011/03/colin/'
            }, {
                image: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/slides/wojno-3.jpg',
                title: 'Image Credit: Colin Wojno',
                thumb: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/thumbs/wojno-3.jpg',
                url: 'http://www.nonsensesociety.com/2011/03/colin/'
            }, {
                image: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/slides/shaden-1.jpg',
                title: 'Image Credit: Brooke Shaden',
                thumb: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/thumbs/shaden-1.jpg',
                url: 'http://www.nonsensesociety.com/2011/06/brooke-shaden/'
            }, {
                image: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/slides/shaden-2.jpg',
                title: 'Image Credit: Brooke Shaden',
                thumb: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/thumbs/shaden-2.jpg',
                url: 'http://www.nonsensesociety.com/2011/06/brooke-shaden/'
            }, {
                image: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/slides/shaden-3.jpg',
                title: 'Image Credit: Brooke Shaden',
                thumb: 'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/thumbs/shaden-3.jpg',
                url: 'http://www.nonsensesociety.com/2011/06/brooke-shaden/'
            }],
            // Theme Options               
            progress_bar: 1, // Timer for each slide                            
            mouse_scrub: 0
        });
    });
</script>

除了图像之外,我的所有设置都符合预期。有趣的是,当我查看源时,它会显示到图像的链接,就像手动输入的链接一样。我试着把数据放在一个数组中,然后动态显示输出,但仍然没有成功。我在源代码中得到了相同的结果。{image :'http://buildinternet.s3.amazonaws.com/projects/supersized/3.2/thumbs/kazvan-1.jpg'},

为什么它不从回声中加载图像,但它显示它在源中。

做这件事要非常非常小心。您直接输出到一个Javascript代码块中,这意味着ALL的输出必须创建语法有效的JS代码。一个错误放置的'可以杀死整个脚本块。

为了安全起见,您应该通过json_encode()进行所有输出,这可以保证您不会引入语法错误。

例如

random: <?php echo json_encode(of_get_option('random', '0')); ?> , // Randomize slide order (Ignores start slide)

考虑这样一个案例:

<?php
$name = "Miles O'Brien";
?>
<script type="text/javascript">
var name = '<?php echo $name; ';
</script>

你最终会生产:

var name = 'Miles O'Brien';
                   ^--- syntax error, terminating the string early.

我建议在清晰的php代码中创建json,然后将该json包含到javascript表达式中。

代码会更好。

你犯错误的机会更少(比如用引号)。

您需要确保在php大括号的两侧放置引号,否则javascript将不会将其作为字符串接收。例如

random                  :   '<?php echo of_get_option('random', '0'); ?>'