如何在不提取的情况下列出zip文件中文件夹的子文件夹


How to list subfolders of a folder inside zip file without extracting?

>我正在使用php ziparchive函数打开zip文件,并希望列出位于zip文件中的文件夹的所有子文件夹。例如。。。World.zip包含一个文件夹国家,foo和bar,我想列出该国家/地区文件夹的所有状态文件夹的名称,但不是foo和bar

我在手册上找到了这个注释,我从手册中获得了大部分代码这取决于遍历文件总数

我重构了它以满足您的需求,这是重构后的代码

<?php
$filePath = 'zip/file.zip';
$za = new ZipArchive();
if ($za->open($filePath) !== true) { // check for the zip archive
    echo "archive doesn't exist or it's on Read-only mode ";
} else {
    $Tree = $pathArray = array(); //empty arrays
    for ($i = 0; $i < $za->numFiles; $i++) {
        $path = $za->getNameIndex($i);
        $pathBySlash = array_values(explode('/', $path));
        $c = count($pathBySlash);
        $temp = &$Tree;
        for ($j = 0; $j < $c - 1; $j++)
            if (isset($temp[$pathBySlash[$j]]))
                $temp = &$temp[$pathBySlash[$j]];
            else {
                $temp[$pathBySlash[$j]] = array();
                $temp = &$temp[$pathBySlash[$j]];
            }
        if (substr($path, -1) == '/')
            $temp[$pathBySlash[$c - 1]] = array();
        else
            $temp[] = $pathBySlash[$c - 1];
    }
    $array = $Tree['folder_name_to_list_its_files'];
    // First style of Displaying 
    echo "<pre>";
    print_r($array);
    // Second style of Displaying
    foreach ($array as $key => $value) {
        foreach ($value as $val) {
            echo $key . " | " . $val . "<br /> 'n";
        }
    }
    echo "</pre>";
}