我在尝试获取项目的详细信息页面时遇到此错误。这是给学校的，我还不太懂PHP。"您的SQL语法有错误；请查看与MySQL服务器版本相对应的手册，以获取在第1行"附近使用的正确语法"
这是该页面的代码。
<?php
require_once('connection.php');
mysqli_select_db($conn, $dbname);
$recordID = $_GET['recordID'];
$query_Shoe_Details = "SELECT * FROM Products WHERE Shoe_Brand = $recordID";
$Shoe_Details = mysqli_query($conn, $query_Shoe_Details) or die(mysqli_error(($conn)));
$row_Shoe_Details= mysqli_fetch_assoc($Shoe_Details);
$totalRows_Shoe_Details = mysqli_num_rows($Shoe_Details);
?>
<!DOCTYPE html>
<html>
<head>
<title>details</title><?php include 'connection.php';?>
</head>
<body>
<p>Product Name: <?php echo $row_Shoe_Details['Product_Name']; ?></p>
<p><img src=
"images/%3C?php%20echo%20$row_Shoe_Details['Image_Name'];%20?%3E"></p>
<p>Description: <?php echo $row_Shoe_Details['Product_Description']; ?></p>
<p>Price: $<?php echo $row_Shoe_Details['Product_Price']; ?></p><?php
mysqli_free_result($Shoe_Details);
?>
</body>
</html>将查询更改为，使用单引号
$query_Shoe_Details = "SELECT * FROM Products WHERE Shoe_Brand = '$recordID'";
也删除此<?php include 'connection.php';?>，无需再次包含
Pl. prepare connection.php file in followng way like
$dbHost = '';
$dbUser = '';
$dbPass = '';
$dbName = '';
// setting up the web root and server root for
// this shopping cart application
$con=mysql_connect('','','');
if(!$con)
{
die('connection failed');
}
$db=mysql_select_db('',$con);
if(!$db)
{
die('db is not selected');
}
pass proper value in this syntax save it and in your code remove second line and test then and give feedback