这是我的第一个问题,所以我希望我能按照它应该做的做每件事。
我有两个具有多对多关系的学说实体,这很好,但我也想在多对多表上添加一个额外的检查。问题是在DQL中,我无法访问正确的列。
我想到了两种可能性:抽象父类或原生查询。我将粘贴下面的本地查询,但这不是我所希望的,因为我们必须复制并粘贴它。
所以我想使关系+类型。因此,对于这个例子,我还需要检查类型="Gallery"
gallery_object(表)
id,标记,已删除
1,赞助商,0
media_relations(表)
id,mediaid,type,typeId
1,37,画廊,1
媒体文件
id,userid,filename,filepath,filesize,mime_type,date,deleted
37,4533882_10151332524797037_1940030593_n_20.jpg,/resources/upload/www/,82724,image/jpeg,2013-01-25 15:04:46,0
$rsm = new ResultSetMapping;
$rsm->addEntityResult(Helper::getNamespace('Gallery', 'Models/Entities') . "Object", 'o')
->addFieldResult('o', 'id', 'id')
->addFieldResult('o', 'tag', 'tag')
->addFieldResult('o', 'deleted', 'deleted')
->addJoinedEntityResult(ltrim(Helper::getNamespace('Media', 'Models/Entities') . "Media", ''''), 'm', 'o', 'file')
->addFieldResult('o', 'file', 'id')
->addFieldResult('m', 'mid', 'id')
->addFieldResult('m', 'user', 'userid')
->addFieldResult('m', 'filename', 'filename')
->addFieldResult('m', 'filepath', 'filepath')
->addFieldResult('m', 'filesize', 'filesize')
->addFieldResult('m', 'mime_type', 'mime_type')
->addFieldResult('m', 'date', 'date')
->addFieldResult('m', 'mdeleted', 'deleted');
$sql = "SELECT o.id AS oid, m.id as file, o.tag, o.deleted, m.id AS mid, m.userid, m.filename, m.filepath, m.filesize, m.mime_type, m.date, m.deleted as mdeleted
FROM gallery_object as o
INNER JOIN media_relations mr ON (mr.typeid = o.id AND mr.type = 'Gallery')
INNER JOIN media_files m ON (mr.mediaid = m.id)";
$result = $this->_em->createNativeQuery($sql, $rsm)->getResult();
return $result;
实体看起来像
/**
* Media entity
*
* @Entity(repositoryClass = "iTet'Application'Modules'Media'Models'Repositories'Media")
* @Table(name="media_files")
* @author Stephen Fenne
*/
class Media
{
/**
* @Id
* @Column(type="integer")
* @GeneratedValue
* @var int
*/
protected $id;
/**
* @ManyToOne(targetEntity="iTet'Application'Modules'Core'User'Models'Entities'User")
* @JoinColumn(name="userId", referencedColumnName="id")
* @var int
*/
protected $user;
/**
* @Column(length = 100)
* @var string
*/
protected $filename;
/**
* @Column
* @var string
*/
protected $filepath;
/**
* @Column(type = "integer")
* @var int
*/
protected $filesize;
/**
* @Column
* @var string
*/
protected $mime_type;
/**
* @Column(type = "datetime", nullable=true)
* @var 'DateTime
*/
protected $date;
/**
* @Column(type = "integer")
* @var int
*/
protected $deleted = false;
--
/**
*
* @Entity(repositoryClass="iTet'Application'Modules'Gallery'Models'Repositories'Object")
* @Table(name="gallery_object")
* @author Ward Peeters <ward@coding-tech.com>
* @package
*/
class Object
{
/** @Id
* @Column(type="integer")
* @GeneratedValue
* @var int */
protected $id;
/** @ManyToMany(targetEntity="iTet'Application'Modules'Media'Models'Entities'Media")
* @JoinTable(name="media_relations",
* joinColumns={@JoinColumn(name="typeid", referencedColumnName="id")},
* inverseJoinColumns={@JoinColumn(name="mediaid", referencedColumnName="id")}
* )
* @var Media */
protected $file;
/** @Column
* @var string */
protected $tag;
/** @Column(type="integer")
* @var bool */
protected $deleted = false;
根据我所能收集的信息,您的选择如下:
- 引入一个实体来表示
media_relations
表中的条目,以及与其他表的适当关联 - 通过类表继承引入"媒体关系"层次结构(为不同的"类型"建模),并仅对"库"类型进行查询。条令继承文件
在这两种情况下,您都会将底层表暴露给Doctrine,这样您就可以使用DQL来获取所需的数据。
HTH