使用PHP从数据库中获取数据,在谷歌地理图


Using PHP to with data taken from a database, in Google GeoChart

我试图在GeoChart上显示数据,这是从'population'数据库中提取的,代码如下所示:

<!DOCTYPE html>
<html>
  <head>
    <script type='text/javascript' src='https://www.google.com/jsapi'></script>
    <script type='text/javascript'>
     google.load('visualization', '1', {'packages': ['geochart']});
     google.setOnLoadCallback(drawMarkersMap);
      function drawMarkersMap() {
      var data = google.visualization.arrayToDataTable([
       <?php 
        echo '["City","Population"],';
        require_once('connect_population.php');
        try{
        $query = "SELECT City, People FROM population";
        $statement = $db->query($query);
        while($row = $statement->fetch(PDO::FETCH_ASSOC)){
            echo '["'.$row["City"].'",'.$row["People"].'],';
        }
        }catch(PDOException $e){
            $message = '<p>Something went wrong!</p><p>' . $e->getMessage() . '</p>';
        }
        ?>
      ]);
      var options = {
        region: 'GB',
        displayMode: 'markers',
        colorAxis {colors: ['red', 'yellow']}
      };
      var chart = new google.visualization.GeoChart(document.getElementById('chart_div'));
      chart.draw(data, options);
    };
        </script>
      </head>
      <body>
        <div id="chart_div" style="width: 900px; height: 500px;"></div>
      </body>
    </html>

PHP仅在向'data'变量中添加数据时使用,并且在PHP部分之后,应该包含以下内容:

var data = google.visualization.arrayToDataTable([
["City","Population"],["London",7172091],["Bristol",420556],["Liverpool",469017],["Leeds",443247],["Birmingham",970892],["Manchester",394269],["Newcastle",655875],["Leicester",330574],["Belfast",276459],["Glasgow",629501],["Sheffield",439866],["Edinburgh",430082]    
]);

在浏览器中运行文件时,我遇到了一个问题,因为没有显示任何内容。使用'inspect element',会在该行显示一个意外的标记错误:

colorAxis {colors: ['red', 'yellow']}

在options变量中

我认为这是设置GeoChart的colorAxis的正确方法?

任何帮助将非常感激,因为我仍在学习如何使用PHP和SQL。

你只是缺少一个冒号:

var options = {
   region: 'GB',
   displayMode: 'markers',
   colorAxis : {colors: ['red', 'yellow']}
};
             ^

否则你的代码运行良好-> http://jsfiddle.net/tnxhg08r/