我使用API并将JSON数组解码为PHP数组,但当我使用foreach循环时,它并没有给我特定的值。以下是原始JSON数组的一个片段:
"playerCredentials": {
"observerEncryptionKey": "blahblah",
"dataVersion": 0,
"playerId": 8675309,
"serverPort": 0,
"observer": true,
"summonerId": 0,
"championId": 0,
"observerServerIp": "111.111.111.111",
"gameId": 123456789,
"observerServerPort": 4388,
"lastSelectedSkinIndex": 0
},
然后,我运行了这个代码:
$array = json_decode($json_array, true);
然后将上述内容转化为:
{ ["playerCredentials"]=> array(11)
{
["observerEncryptionKey"]=> string(32) "blahblah"
["dataVersion"]=> int(0)
["playerId"]=> int(8675309)
["serverPort"]=> int(0)
["observer"]=> bool(true)
["summonerId"]=> int(0)
["championId"]=> int(0)
["observerServerIp"]=> string(14) "111.111.111.111"
["gameId"]=> int(123456789)
["observerServerPort"]=> int(4338)
["lastSelectedSkinIndex"]=> int(0)
}
然而,当我运行这个foreach循环时:
foreach($array['playerCredentials'] as $stats) {
echo $stats['playerId'];
}
我得到的回报只有82(我甚至不知道这是从哪里来的)。但是,如果我运行这个:
foreach($array['playerCredentials'] as $stats) {
echo $stats."<br>";
}
我得到了整个阵列中的所有信息:
blahblah
0
8675309
0
true
0
0
111.111.111.111
123456789
4338
0
我怎么能只得到一块呢?
{
"playerCredentials": {
"observerEncryptionKey": "blahblah",
"dataVersion": 0,
"playerId": 8675309,
"serverPort": 0,
"observer": true,
"summonerId": 0,
"championId": 0,
"observerServerIp": "111.111.111.111",
"gameId": 1347503269,
"observerServerPort": 8088,
"lastSelectedSkinIndex": 0
},
"dataVersion": 0,
"gameName": "match-1347503269",
"reconnectDelay": 0,
"game": {
"practiceGameRewardsDisabledReasons": {
"array": []
},
"glmSecurePort": 0,
"queuePosition": 0,
"playerChampionSelections": {
"array": [
{
"spell1Id": 4,
"spell2Id": 7,
"championId": 25,
"summonerInternalName": "nameone",
"selectedSkinIndex": 0,
"dataVersion": 0
},
{
"spell1Id": 12,
"spell2Id": 4,
"championId": 13,
"summonerInternalName": "nametwo",
"selectedSkinIndex": 0,
"dataVersion": 0
}
]
在循环中,$stats
指的是数组中每个元素的值。我想你在找$array['playerCredentials']['playerId'];
。如果你想迭代播放器的所有属性,你可以这样做:
foreach ($array['playerCredentials'] as $key => $value) {
printf('%s => %s<br />', $key, $value);
}
如果使用PHP>5.4:,可以这样做
<?php
$json='{
"playerCredentials": {
"observerEncryptionKey": "blahblah",
"dataVersion": 0,
"playerId": 8675309,
"serverPort": 0,
"observer": true,
"summonerId": 0,
"championId": 0,
"observerServerIp": "111.111.111.111",
"gameId": 123456789,
"observerServerPort": 4388,
"lastSelectedSkinIndex": 0
}
}';
$playerCredentials = json_decode($json, true)["playerCredentials"];
foreach($playerCredentials as $key => $value) {
echo "key: ".$key."'n";
echo "value: ".$value."'n";
}
下面是一个演示:https://eval.in/137205
或者,如果使用PHP<5.4,您将无法使用json_decode嵌套阵列访问,所以您只需要这样做:
<?php
$json='{
"playerCredentials": {
"observerEncryptionKey": "blahblah",
"dataVersion": 0,
"playerId": 8675309,
"serverPort": 0,
"observer": true,
"summonerId": 0,
"championId": 0,
"observerServerIp": "111.111.111.111",
"gameId": 123456789,
"observerServerPort": 4388,
"lastSelectedSkinIndex": 0
}
}';
$result = json_decode($json, true);
foreach($result["playerCredentials"] as $key => $value) {
echo "key: ".$key."'n";
echo "value: ".$value."'n";
}
下面是一个演示:https://eval.in/137209
你可以试试这个
<?php
$json_array ='{
"playerCredentials": {
"observerEncryptionKey": "blahblah",
"dataVersion": 0,
"playerId": 8675309,
"serverPort": 0,
"observer": true,
"summonerId": 0,
"championId": 0,
"observerServerIp": "111.111.111.111",
"gameId": 123456789,
"observerServerPort": 4388,
"lastSelectedSkinIndex": 0
}
}';
$array = json_decode($json_array, true);
foreach($array as $playerCredentials) {
echo $playerCredentials['playerId'];
}
输出
8675309
演示