将数组分解为键->；值数组 - Explode array into a key->value array

我有以下字符串：

名称定位电话中断名称定位电话断开名称定位电话

我从一个使用DOM的HTML页面的cURL中得到了这个。

我的最终结果必须是一个JSON文件，如：

Shop 1: { name: "example", location: "example", telephone: "0123"}
Shop 2: { name: "example", location: "example", telephone: "0123"}

但我知道，首先我必须拆分字符串，我尝试了这个

$shops = explode("break",$result);
$values = array();
foreach ($shops as $shop) {
    $values = explode("_", $shop);
    foreach($values as $value) {
        $name = $value[0];
        $location = $value[1];
        $tel = $value[2];
    }
}

但它不起作用。有人能帮我吗？

你在错误的值上爆炸：

Name_Location_Telephone_break_Name_Location_Telephone etc...

将变成一个数组：

0 => 'Name_Location_Telephone_'
1 => '_Name_Location_Telephone_'
2 => '_Name_Location_Telephone_'
etc...

当您分解这些时，第一个将在索引0处具有Name，但随后在所有后续分解的索引1处。

你应该在_break_上爆炸。

如果你做过任何基本的调试，比如var_dump($shops)和var_dump($values)，你就会看到事情是如何变化的。

1）第一次爆炸会保留一些修剪下划线。

2）您必须使用json_encode方法将数组转换为json数据

一个你可以做的例子

$result = "Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone_break_";
$shops = explode("_break_",$result);
foreach($shops as $key => $shop) {
    $res["Shop ".$key] = explode('_', $shop);
}
$jsonData = json_encode($res);

这并不是编写foreach的确切方式。它不同于Java。签出：http://php.net/manual/en/control-structures.foreach.php例如，从现在起不要犹豫（PHP API非常好）

您几乎接近所需的结果。尝试遵循

 $shops = explode("_break_",$result);
 $jsonArray = array();
 foreach ($shops as $shop){
     // three elements are same in response no need to worry just explode in array of three elements.
  $value = explode("_", $shop); 
   // assign prepared array or print it according to your business logic.
   $jsonArray[] = array ('name'=>$value[0], 'location'=>$value[1], 'telephone'=>$value[2]); 
 }
 //here you can encode your final multi dimensional array to json string.
echo json_encode($jsonArray);

它不起作用，因为您的第一次爆炸保留了一些修剪下划线。

要么做

$shops = explode("_break_",$result);

或

$shops = trim(explode("break",$result), "_");

试试这个：

$result = "Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone";
$shops = explode("_break_",$result);
$results = array();
$index = 1;
foreach ($shops as $shop) {
    $values = explode("_", $shop);
    $results["Shop $index"] = [
        'name' => $values[0],
        'location' => $values[1],
        'telephone' => $values[2],
    ];
    $index++;
}
print_r($results);

结果是：

Array
(
    [Shop 1] => Array
        (
            [name] => Name
            [location] => Location
            [telephone] => Telephone
        )
    [Shop 2] => Array
        (
            [name] => Name
            [location] => Location
            [telephone] => Telephone
        )
    [Shop 3] => Array
        (
            [name] => Name
            [location] => Location
            [telephone] => Telephone
        )
    [Shop 4] => Array
        (
            [name] => Name
            [location] => Location
            [telephone] => Telephone
        )
)

在第一个explode之后只有break有多余的"_"，这就是为什么结果可能会出错的原因。

第一次爆炸后，您需要修剪$shops数组中字符串最后一个的"_"。

<?php
    $result = "Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone";
    $shops = explode("break",$result);
    echo json_encode($shops)."'n";
    $values = array();
    foreach ($shops as $shop){
        $values = explode("_", trim($shop, '_'));
        echo json_encode($values)."'n";
        $name = $values[0];
        $location = $values[1];
        $tel = $values[2];
        echo $name."'n";
    }
?>

结果是

["Name_Location_Telephone_","_Name_Location_Telephone_","_Name_Location_Telephone_","_Name_Location_Telephone"]
["Name","Location","Telephone"]
Name
["Name","Location","Telephone"]
Name
["Name","Location","Telephone"]
Name
["Name","Location","Telephone"]
Name