我很难在引号中连接引号这个问题可能对任何人都没有用,但我真的需要这个来解决。
这是代码,我希望它能正常工作,但似乎我在某个地方犯了错误。
$query = "SELECT message,time,user_id FROM post ORDER BY time DESC";
$query_run = mysqli_query($con,$query);
while($row = mysqli_fetch_assoc($query_run))
{
$message = $row['message'];
$user_id = $row['user_id'];
echo "<img src= 'https://graph.facebook.com/'.'$user_id'.'/picture?width=50&height=40' class = 'post_dp'>";
}
我不知道如何将user_id
与链接连接起来。
$query = "SELECT message,time,user_id FROM post ORDER BY time DESC";
$query_run = mysqli_query($con,$query);
while($row = mysqli_fetch_assoc($query_run))
{
$message = $row['message'];
$user_id = $row['user_id'];
echo "<img src= 'https://graph.facebook.com/". $user_id ."/picture?width=50&height=40' class = 'post_dp'>";
}
如果字符串以双引号开始,则必须以双引号结束。
echo "<img src= 'https://graph.facebook.com/".'$user_id'."/picture?width=50&height=40' class = 'post_dp'>";
但是,由于php双引号可以转换变量,您根本不需要关闭它们并重新打开:
echo "<img src= 'https://graph.facebook.com/$user_id/picture?width=50&height=40' class = 'post_dp'>";