我正在尝试使用jQuery更新数据库。该函数运行良好,但仅运行一次。如果我想再次更新数据库,我必须刷新页面并清除缓存。我正在使用MODX Revolution,我不确定这是否与这个问题有关。这是代码:
<html>
<head>
<script language="javascript" type="text/javascript" src="//ajax.aspnetcdn.com/ajax/jQuery/jquery-1.8.3.min.js"></script>
</head>
<body>
<script>
$(document).ready(function(){
$('#paina').submit( function updateTitle() {
var mail = $("#output").val();
$.ajax({
type: "POST",
url: "gettable.php",
data: "mail="+ mail,
cache: false,
success: function(data){
alert(mail);
}
});
return false;
});
});
</script>
<form id="paina" name="test" action="javascript:updateTitle()" method="post">
<input type="text" id="output">
<input type="Submit" value="Update">
</form>
</body>
</html>
PHP:
<?php
$mail=$_POST["mail"];
$mysqli = mysqli_connect("url", "user", "password", "database_name");
mysqli_query($mysqli, "UPDATE modx_site_content SET pagetitle='$mail' WHERE longtitle='jee'");
echo "Updated!";
$mysqli->close();
从jQuery文档:
注意:将缓存设置为false将仅适用于HEAD和GET请求
丑陋的修复:在查询字符串中附加一个随机参数:
$.ajax({
type: "POST",
url: "gettable.php",
data: "mail="+ mail + "×tamp=" + new Date(), // Will append the current date in milliseconds since January 1, 1970 (correct me if I'm wrong).
cache: false,
success: function(data){
alert(mail);
}
});
尝试将ajax更改为有助于调试,我还向数据添加了一个对象,并将sync设置为false,以确保ajax在返回之前完成执行
$(document).ready(function(){
$('#paina').submit( function() {
$.ajax({
type: "POST",
url: "gettable.php",
data: {mail: mail},
cache: false,
async: false,
success: function(data){
alert(mail);
},
error function(){
alert("Failed");
}
});
});
});
您也不需要在表单上执行操作,因为jQuery正在处理
<form id="paina" name="test" action="" method="post">
感谢您的提示。我找到了解决方案,MODX Revolution使用xPDO数据库连接,所以我不得不将PHP代码更改为:
$mail=$_POST["mail"];
$dsn = 'mysql:host=localhost;dbname=databasename;port=3306;charset=utf-8';
$xpdo = new xPDO($dsn,'user','password');
$results = $xpdo->query("UPDATE modx_site_content SET pagetitle='$mail' WHERE longtitle='jee'");