我需要在我的ajax请求中添加一些内容，以显示它从<span id="total_vote_down_<?php echo $mes_id2; ?>">中减去1。现在，我的ajax只是在<span id="total_vote_up_<?php echo $mes_id1; ?>">的值上加1，我需要它在同一函数中从<span id="total_vote_up_<?php echo $mes_id1; ?>">中减去1。我知道我的代码太草率了。。。。请耐心等待…
顺便说一句，我知道ajax实际上并没有添加和减少任何内容，它只是为客户演示它，只是不知道用什么更好的方法来表达我的问题
一般.js
$(".vote").click(function()
{
var id = $(this).attr("id");
var name = $(this).attr("name");
var eData = $(this).attr("data-options");
var dataString = 'id='+ id + '&' + eData ;
var parent = $(this);
if(name=='up')
{
$(this).fadeIn(200).html('');
$.ajax({
type: "POST",
url: "up.php",
data: dataString,
cache: false,
success: function(data) { $('#total_' + parent.attr("id")).text(data); }
});
}
else
{
$(this).fadeIn(200).html('');
$.ajax({
type: "POST",
url: "down.php",
data: dataString,
cache: false,
success: function(data) { $('#total_' + parent.attr("id")).text(data); }
});
}
});
index.php
<div id="main">
<div id="left">
<span class='up'><a title="vote_down_" id="vote_up_<?php echo $mes_id1; ?>" class="vote" name="up" data-options="key1=<?php echo $mes_id1;?>&key2=<?php echo $mes_id2;?>&key3=<?php echo $totalvotes1;?>&key4=<?php echo $totalvotes2;?>"> <img src="up.png" alt="Down" /></a></span><br />
<span id="total_vote_up_<?php echo $mes_id1; ?>"><?php echo $totalvotes1; ?></span><br />
</div>
<div id="message">
<?php echo $message1; ?>
</div>
<div class="clearfix"></div>
</div>
<div id="main">
<div id="right">
<br />
<span id="total_vote_down_<?php echo $mes_id2; ?>"><?php echo $totalvotes2; ?></span><br />
<span class='down'><a id="vote_down_<?php echo $mes_id2; ?>" class="vote" name="down" data-options="key1=<?php echo $mes_id1;?>&key2=<?php echo $mes_id2;?>"><img src="down.png" alt="Down" /></a></span>
</div>
<div id="message">
<?php echo $message2; ?>
</div>
<div class="clearfix"></div>
</div>
这是up.php
<?php
session_start();
include("config.php");
$ip=$_SERVER['REMOTE_ADDR'];
$mes_id1 = $_POST['key1'];
$mes_id2 = $_POST['key2'];
$totalvotes1 = $_POST['key3'];
$totalvotes2 = $_POST['key4'];
$new_totalvotes1 = $totalvotes1 + 1;
$new_totalvotes2 = $totalvotes2 - 1;
$ip_sql=mysql_query("select ip_add from Voting_IP where mes_id_fk='$mes_id1' and ip_add='$ip'");
$count=mysql_num_rows($ip_sql);
$ip_sql2=mysql_query("select ip_add from Voting_IP where mes_id_fk='$mes_id2' and ip_add='$ip'");
$count2=mysql_num_rows($ip_sql2);
// if the user has already voted, execute script
if($count==0 && $count2!=0)
{
$sql = "update Messages set totalvotes=totalvotes+1 where mes_id='$mes_id1'";
mysql_query( $sql);
$sql_in = "insert into Voting_IP (mes_id_fk,ip_add) values ('$mes_id1','$ip')";
mysql_query( $sql_in);
$sql = "update Messages set totalvotes=totalvotes-1 where mes_id='$mes_id2'";
mysql_query( $sql);
$sql_in = "DELETE FROM Voting_IP WHERE mes_id_fk='$mes_id2'";
mysql_query( $sql_in);
echo $new_totalvotes1;
// if the user has not voted, execute script
}
else if($count==0 && count2==0)
{
$sql = "update Messages set totalvotes=totalvotes+1 where mes_id='$mes_id1'";
mysql_query( $sql);
$sql_in = "insert into Voting_IP (mes_id_fk,ip_add) values ('$mes_id1','$ip')";
mysql_query( $sql_in);
echo $new_totalvotes1;
}
?>
down.php与up相同，只是具有相反的值
如果在PHP中创建关联数组，则可以使用json_encode将其转换为JSON。类似这样的东西：
// obviously this will be constructed dynamically from your database
$d = array('Will' => 10, 'Henry' => 12);
// echo as json
echo json_encode($d);
然后在您的JavaScript中：
$.ajax({
type: "POST",
url: "down.php",
data: dataString,
cache: false,
dataType: "json",
success: function(data) {
// here data will look like { "Will":10, "Henry": 20 };
// I'm going to assume `total_will` is the total votes for william
var candidate;
for (candidate in data) {
$("#total_" + candidate).text(data[candidate]);
}
// now #total_Will has the text 10
// and #total_Henry has the text 20
}
});