我有一个静态代码来更新一些选择框。
原始结构代码:
$result = "
({
'options': [
{'value': '','description': '(pick an item)'},
{'value': 'test','description': 'test'},
{'value': 'test_2','description': 'test_2'}
]
});
";
我正试图将其动态化,并连接到Postgresql数据库中的表,但我的代码不起作用。
这是我的代码:
if($value=="asus"){
require("includes/connection.php");
$sth = $dbh->prepare( "SELECT * FROM mapa_ferias WHERE area = 'Asus' " );
$sth->setFetchMode(PDO::FETCH_ASSOC);
$sth->execute();
$result = "
({
'options': [";
while($row = $sth->fetch()) {
$result += "{'value': '" + $row['nome'] + "','description': '" + $row['nome'] + "'},";
}
$result +=
"]
});
";
}
我希望你能帮我。提前谢谢。
请不要尝试自己构建JSON数据。。PHP有一个函数:json_encode()
if ($value=="asus"){
require("includes/connection.php");
$sth = $dbh->prepare( "SELECT * FROM mapa_ferias WHERE area = 'Asus' " );
$sth->setFetchMode(PDO::FETCH_ASSOC);
$sth->execute();
$options = array();
while($row = $sth->fetch()) {
$options[] = array(
'value' => $row['nome'],
'description' => $row['nome']
);
}
$sth->closeCursor();
$result = '('.json_encode(array(
'options' => $options
)).')';
}