将字符串划分为关联数组 - Divide string into associtive array

Divide string into associtive array

本文关键字：关联数组划分字符串 | 更新日期: 2023-09-27

我有一个字符串：

$string = 'A0695/16 NOTAMN Q) EHAA/QARLT/I /NBO/E /000/999/5155N00430E073 A) EHAA B) 1605260001 C) 1608260900 EST E) REF AIP NETHERLANDS ENR 3.2 UT601 ADD TO ROUTE REMARKS: NOT AVBL FOR TRAFFIC DEP/ARR ETNG, EDDK AND ETNN DURING THE OPENING OF EHEH 0600-2300 (0500-2200). THESE FLIGHTS WILL HAVE TO REROUTE.';

我想把这个字符串拆分成一个关联数组。

$result['Q)'] = 'EHAA/QARLT/I /NBO/E /000/999/5155N00430E073';
$result['A)'] = 'EHAA';
$result['B)'] = '1605260001';
$result['C)'] = '1608260900 EST';

等等。

我设法用将其放入阵列中

$result = preg_split("/.')/", $string);

它给了我一个数组，但我需要密钥是'a)', 'b)'等

有人能帮我吗？

使用具有特定regexp模式的preg_match_all函数(命名子任务(和array_combine函数(以获得各自的键/值对(的解决方案：

$string = 'A0695/16 NOTAMN Q) EHAA/QARLT/I /NBO/E /000/999/5155N00430E073 A) EHAA B) 1605260001 C) 1608260900 EST E) REF AIP NETHERLANDS ENR 3.2 UT601 ADD TO ROUTE REMARKS: NOT AVBL FOR TRAFFIC DEP/ARR ETNG, EDDK AND ETNN DURING THE OPENING OF EHEH 0600-2300 (0500-2200). THESE FLIGHTS WILL HAVE TO REROUTE.';
preg_match_all("/(?<k>[A-Z]')) (?<v>.+?)(?= [A-Z]')|$)/", $string, $matches);
// 'k'/'v' are key/value
$result = array_combine($matches['k'], $matches['v']);
print_r($result);

输出：

Array
(
    [Q)] => EHAA/QARLT/I /NBO/E /000/999/5155N00430E073
    [A)] => EHAA
    [B)] => 1605260001
    [C)] => 1608260900 EST
    [E)] => REF AIP NETHERLANDS ENR 3.2 UT601 ADD TO ROUTE REMARKS: NOT AVBL FOR TRAFFIC DEP/ARR ETNG, EDDK AND ETNN DURING THE OPENING OF EHEH 0600-2300 (0500-2200). THESE FLIGHTS WILL HAVE TO REROUTE.
)

愚蠢格式的另一个愚蠢解决方案，因为为什么不呢。

  $string = 'A0695/16 NOTAMN Q) EHAA/QARLT/I /NBO/E /000/999/5155N00430E073 A) EHAA B) 1605260001 C) 1608260900 EST E) REF AIP NETHERLANDS ENR 3.2 UT601 ADD TO ROUTE REMARKS: NOT AVBL FOR TRAFFIC DEP/ARR ETNG, EDDK AND ETNN DURING THE OPENING OF EHEH 0600-2300 (0500-2200). THESE FLIGHTS WILL HAVE TO REROUTE.';
  $foo = preg_split('/([A-Z]')) /', $string, 0, PREG_SPLIT_DELIM_CAPTURE);
  $ret = [];
  foreach (range(1, count($foo) - 1, 2) as $i)
  {
    $ret[$foo[$i]] = $foo[$i + 1];
  }
  print_r($ret);

打印：

Array (
    [Q)] => EHAA/QARLT/I /NBO/E /000/999/5155N00430E073 
    [A)] => EHAA 
    [B)] => 1605260001 
    [C)] => 1608260900 EST 
    [E)] => REF AIP NETHERLANDS ENR 3.2 UT601 ADD TO ROUTE REMARKS: NOT AVBL FOR TRAFFIC DEP/ARR ETNG, EDDK AND ETNN DURING THE OPENING OF EHEH 0600-2300 (0500-2200). THESE FLIGHTS WILL HAVE TO REROUTE. )

与其说是高效，不如说是异想天开：

$p = preg_split('~(?<!'S)([A-Z]'))'s+~', $string, -1, PREG_SPLIT_DELIM_CAPTURE);
$result = [];
if (count($p) > 1) {
    unset($p[0]);
    while($p) { 
        $result[array_shift($p)] = array_shift($p);
    }
}
print_r($result);