我有一个Laravel User模型，该模型对username和email具有唯一的验证规则。在我的Repository中，当我更新模型时，我将重新验证字段，这样就不会出现所需规则验证的问题:
public function update($id, $data) {
$user = $this->findById($id);
$user->fill($data);
$this->validate($user->toArray());
$user->save();
return $user;
}
在使用
进行测试时失败ValidationException: {"username":["用户名已经存在["]，"email":["该邮件已被占用。"]}
是否有一种方法可以优雅地解决这个问题?
将当前正在更新的实例的id附加到验证器中。
-
传递实例的
id以忽略唯一验证器 -
在验证器中，使用一个参数来检测您是更新还是创建资源。
如果更新，强制唯一规则忽略给定的id:
//rules
'email' => 'unique:users,email_address,' . $userId,
如果正在创建，则照常进行:
//rules
'email' => 'unique:users,email_address',
另一种优雅的方式…
在您的模型中，创建一个静态函数:public static function rules ($id=0, $merge=[]) {
return array_merge(
[
'username' => 'required|min:3|max:12|unique:users,username' . ($id ? ",$id" : ''),
'email' => 'required|email|unique:member'. ($id ? ",id,$id" : ''),
'firstname' => 'required|min:2',
'lastname' => 'required|min:2',
...
],
$merge);
}
创建验证:
$validator = Validator::make($input, User::rules());
验证更新:
$validator = Validator::make($input, User::rules($id));
更新时的验证，带有一些附加规则:
$extend_rules = [
'password' => 'required|min:6|same:password_again',
'password_again' => 'required'
];
$validator = Validator::make($input, User::rules($id, $extend_rules));
好了。
Working within my question:
public function update($id, $data) {
$user = $this->findById($id);
$user->fill($data);
$this->validate($user->toArray(), $id);
$user->save();
return $user;
}
public function validate($data, $id=null) {
$rules = User::$rules;
if ($id !== null) {
$rules['username'] .= ",$id";
$rules['email'] .= ",$id";
}
$validation = Validator::make($data, $rules);
if ($validation->fails()) {
throw new ValidationException($validation);
}
return true;
}
是我根据上面公认的答案所做的。
编辑:有了表单请求，一切都变得简单了:
<?php namespace App'Http'Requests;
class UpdateUserRequest extends Request
{
/**
* Determine if the user is authorized to make this request.
*
* @return bool
*/
public function authorize()
{
return true;
}
/**
* Get the validation rules that apply to the request.
*
* @return array
*/
public function rules()
{
return [
'name' => 'required|unique:users,username,'.$this->id,
'email' => 'required|unique:users,email,'.$this->id,
];
}
}
您只需要将UpdateUserRequest传递给您的更新方法，并确保POST模型id。
在Laravel中使用不同列ID进行唯一验证
'UserEmail'=>"required|email|unique:users,UserEmail,$userID,UserID"
或者你可以在你的表单请求中做的是(对于Laravel 5.3+)
public function rules()
{
return [
'email' => 'required|email|unique:users,email,'. $this->user
//here user is users/{user} from resource's route url
];
}
我已经在Laravel 5.6中做过了，它工作了。
'email' => [
'required',
Rule::exists('staff')->where(function ($query) {
$query->where('account_id', 1);
}),
],
'email' => [
'required',
Rule::unique('users')->ignore($user->id)->where(function ($query) {
$query->where('account_id', 1);
})
],
Laravel 5兼容通用方式:
我刚刚遇到了同样的问题，并以一种通用的方式解决了它。如果你创建一个项目，它使用默认规则，如果你更新一个项目，它将检查你的:unique规则，并自动插入一个排除(如果需要)。
创建一个BaseModel类，并让你所有的模型从它继承:
<?php namespace App;
use Illuminate'Database'Eloquent'Model;
class BaseModel extends Model {
/**
* The validation rules for this model
*
* @var array
*/
protected static $rules = [];
/**
* Return model validation rules
*
* @return array
*/
public static function getRules() {
return static::$rules;
}
/**
* Return model validation rules for an update
* Add exception to :unique validations where necessary
* That means: enforce unique if a unique field changed.
* But relax unique if a unique field did not change
*
* @return array;
*/
public function getUpdateRules() {
$updateRules = [];
foreach(self::getRules() as $field => $rule) {
$newRule = [];
// Split rule up into parts
$ruleParts = explode('|',$rule);
// Check each part for unique
foreach($ruleParts as $part) {
if(strpos($part,'unique:') === 0) {
// Check if field was unchanged
if ( ! $this->isDirty($field)) {
// Field did not change, make exception for this model
$part = $part . ',' . $field . ',' . $this->getAttribute($field) . ',' . $field;
}
}
// All other go directly back to the newRule Array
$newRule[] = $part;
}
// Add newRule to updateRules
$updateRules[$field] = join('|', $newRule);
}
return $updateRules;
}
}
现在您可以像以前那样在模型中定义规则:
protected static $rules = [
'name' => 'required|alpha|unique:roles',
'displayName' => 'required|alpha_dash',
'permissions' => 'array',
];
并在控制器中验证它们。如果模型没有验证，它将自动重定向回带有相应验证错误的表单。如果没有验证错误发生，它将继续执行后面的代码。
public function postCreate(Request $request)
{
// Validate
$this->validate($request, Role::getRules());
// Validation successful -> create role
Role::create($request->all());
return redirect()->route('admin.role.index');
}
public function postEdit(Request $request, Role $role)
{
// Validate
$this->validate($request, $role->getUpdateRules());
// Validation successful -> update role
$role->update($request->input());
return redirect()->route('admin.role.index');
}
就是这样!:)请注意，在创建时我们调用Role::getRules()，在编辑时我们调用$role->getUpdateRules() .
我有BaseModel类，所以我需要一些更通用的
//app/BaseModel.php
public function rules()
{
return $rules = [];
}
public function isValid($id = '')
{
$validation = Validator::make($this->attributes, $this->rules($id));
if($validation->passes()) return true;
$this->errors = $validation->messages();
return false;
}
在用户类中，假设我只需要验证电子邮件和姓名:
//app/User.php
//User extends BaseModel
public function rules($id = '')
{
$rules = [
'name' => 'required|min:3',
'email' => 'required|email|unique:users,email',
'password' => 'required|alpha_num|between:6,12',
'password_confirmation' => 'same:password|required|alpha_num|between:6,12',
];
if(!empty($id))
{
$rules['email'].= ",$id";
unset($rules['password']);
unset($rules['password_confirmation']);
}
return $rules;
}
我用phpunit测试了这个，效果很好。
//tests/models/UserTest.php
public function testUpdateExistingUser()
{
$user = User::find(1);
$result = $user->id;
$this->assertEquals(true, $result);
$user->name = 'test update';
$user->email = 'ddd@test.si';
$user->save();
$this->assertTrue($user->isValid($user->id), 'Expected to pass');
}
角色更新的简单例子
// model/User.php
class User extends Eloquent
{
public static function rolesUpdate($id)
{
return array(
'username' => 'required|alpha_dash|unique:users,username,' . $id,
'email' => 'required|email|unique:users,email,'. $id,
'password' => 'between:4,11',
);
}
}
.
// controllers/UsersControllers.php
class UsersController extends Controller
{
public function update($id)
{
$user = User::find($id);
$validation = Validator::make($input, User::rolesUpdate($user->id));
if ($validation->passes())
{
$user->update($input);
return Redirect::route('admin.user.show', $id);
}
return Redirect::route('admin.user.edit', $id)->withInput()->withErrors($validation);
}
}
如果你有另一列被用作外键或索引，那么你也必须在规则中指定，如:
'phone' => [
"required",
"phone",
Rule::unique('shops')->ignore($shopId, 'id')->where(function ($query) {
$query->where('user_id', Auth::id());
}),
],
我调用不同的存储和更新验证类。在我的例子中，我不想更新每个字段，所以我为创建和编辑的公共字段设置了baserrules。为每个类添加额外的验证类。我希望我的例子是有帮助的。我用的是Laravel 4。
模型:
public static $baseRules = array(
'first_name' => 'required',
'last_name' => 'required',
'description' => 'required',
'description2' => 'required',
'phone' => 'required | numeric',
'video_link' => 'required | url',
'video_title' => 'required | max:87',
'video_description' => 'required',
'sex' => 'in:M,F,B',
'title' => 'required'
);
public static function validate($data)
{
$createRule = static::$baseRules;
$createRule['email'] = 'required | email | unique:musicians';
$createRule['band'] = 'required | unique:musicians';
$createRule['style'] = 'required';
$createRule['instrument'] = 'required';
$createRule['myFile'] = 'required | image';
return Validator::make($data, $createRule);
}
public static function validateUpdate($data, $id)
{
$updateRule = static::$baseRules;
$updateRule['email'] = 'required | email | unique:musicians,email,' . $id;
$updateRule['band'] = 'required | unique:musicians,band,' . $id;
return Validator::make($data, $updateRule);
}
控制器:储存方法:
public function store()
{
$myInput = Input::all();
$validation = Musician::validate($myInput);
if($validation->fails())
{
$key = "errorMusician";
return Redirect::to('musician/create')
->withErrors($validation, 'musicain')
->withInput();
}
}
public function update($id)
{
$myInput = Input::all();
$validation = Musician::validateUpdate($myInput, $id);
if($validation->fails())
{
$key = "error";
$message = $validation->messages();
return Redirect::to('musician/' . $id)
->withErrors($validation, 'musicain')
->withInput();
}
}
public static function custom_validation()
{
$rules = array('title' => 'required ','description' => 'required','status' => 'required',);
$messages = array('title.required' => 'The Title must be required','status.required' => 'The Status must be required','description.required' => 'The Description must be required',);
$validation = Validator::make(Input::all(), $rules, $messages);
return $validation;
}
我也有同样的问题。我所做的:添加在我的视图隐藏字段与模型的id和在验证器检查唯一，只有当我从视图得到一些id。
$this->validate(
$request,
[
'index' => implode('|', ['required', $request->input('id') ? '' : 'unique:members']),
'name' => 'required',
'surname' => 'required',
]
);
您可以尝试下面的代码
return [
'email' => 'required|email|max:255|unique:users,email,' .$this->get('id'),
'username' => 'required|alpha_dash|max:50|unique:users,username,'.$this->get('id'),
'password' => 'required|min:6',
'confirm-password' => 'required|same:password',
];
Laravel 5.8 simple and easy
您可以在表单请求中很好地完成这一切…
首先创建一个字段，您可以通过该字段在普通编辑表单中传递id(不可见)。例如,
<div class="form-group d-none">
<input class="form-control" name="id" type="text" value="{{ $example->id }}" >
</div>
…然后确保将Rule类添加到表单请求中，如下所示:
use Illuminate'Validation'Rule;
…添加忽略当前id的唯一规则，如下所示:
public function rules()
{
return [
'example_field_1' => ['required', Rule::unique('example_table')->ignore($this->id)],
'example_field_2' => 'required',
];
…最后，在update方法中键入提示表单请求，就像在store方法中一样，如下所示:
public function update(ExampleValidation $request, Examle $example)
{
$example->example_field_1 = $request->example_field_1;
...
$example->save();
$message = "The aircraft was successully updated";
return back()->with('status', $message);
}
这样你就不会重复不必要的代码:-)
public function rules()
{
if ($this->method() == 'PUT') {
$post_id = $this->segment(3);
$rules = [
'post_title' => 'required|unique:posts,post_title,' . $post_id
];
} else {
$rules = [
'post_title' => 'required|unique:posts,post_title'
];
}
return $rules;
}
对于自定义FormRequest和Laravel 5.7+，你可以像这样获得更新模型的id:
public function rules()
{
return [
'name' => 'required|min:5|max:255|unique:schools,name,'.'Request::instance()->id
];
}
对于使用表单请求的任何人
在我的情况下，我尝试了以下所有方法，但都不起作用:
$this->id, $this->user->id, $this->user .
这是因为我不能直接访问模型$id和$id。
所以我得到了$id从查询使用相同的unique字段，我试图验证:
/**
* Get the validation rules that apply to the request.
*
* @return array
*/
public function rules()
{
$id = YourModel::where('unique_field',$this->request->get('unique_field'))->value('id');
return [
'unique_field' => ['rule1','rule2',Rule::unique('yourTable')->ignore($id)],
];
}
它将100%工作我实现了两种情况，一种情况是相同的表单字段在数据库表product中另一种情况是products_name是表单字段在表中，它的名字是name，我们如何在更新时验证并忽略id。我已经加密了，所以我解密了id，如果你加密了，那么你就会解密，否则就像它来自表单一样传递它。
$request->validate([
'product_code' => 'required|unique:products,product_code,'.decrypt($request->hiddenProductId),
'products_name' => 'required|unique:products,name,'.decrypt($request->hiddenProductId),
]);
这个问题有一个详细而直接的答案，我正在寻找太
https://laravel.com/docs/9.x/validation rule-unique