在删除PDO PHP后填充表


Populating table after delete PDO PHP

当用户登录时,他将转到一个有表的页面,该表在每行上都填充了delete链接。如果我点击删除链接,它将删除记录,但当它刷新页面时,表将不会加载此消息。

Warning: mysql_query(): Access denied for user ''@'host' (using password: NO)
Warning: mysql_query(): A link to the server could not be established in 
Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given

为什么它会让我第一次又一次地填充表呢?这是我的删除代码。

$id_actividades = $_GET['idactividades'];
$stmt = $dbh->prepare("DELETE FROM guaynabodb.actividades WHERE idactividades=:id_actividades");
$stmt -> bindParam(':id_actividades', $id_actividades);
     try{
      $stmt->execute();
     }
     catch (PDOException $ex) {
    echo $ex->getMessage(),'Cannot delete',"'n";
      }
      header('Location: actividades.php');//To redirect
      exit;

这是我拥有表格的页面的代码。它加载后,你登录,但如果我删除一个记录,它不会加载。

  include('../includes/dbschema.php');
      $stmt = $dbh->prepare("SELECT * FROM actividades");
          $stmt->execute();
     print " <h1 id='"h2title'">Calendario de Actividades</h1><br/><br/>";//Print the title header
           echo "<table id='"premiacionguaynabo'"> <tr> <th> No. </th> <th> Fecha </th> <th> Torneo </th> <th> Lugar </th> <th> Organizador </th> <th> Opciones </th> </tr>"; //The table and the headers are created  
             $tno = 0;
              $result = $stmt->fetchall(PDO::FETCH_ASSOC);
              foreach($result as $line){
                $tno = $tno + 1;
     $id = $line["idactividades"];
    print "<tr class='"alt2'">"; 
    print "<td id='"idtorneo'">  $tno  </td>";
    print "<td class='"fechatorneo'"> " . $line['fecha_inicial'] . " al " . $line['fecha_final'] .  "</td>";
    print "<td> <a id='"plinks'"  href='"$picture'" rel='"lightbox'" target='"_top'" title='"Flyer del Torneo'"> " . $line['ntorneo'] . " </a></td>";
    print "<td>" . $line['ltorneo'] . "</td>"; 
    print "<td>" . $line['otorneo'] . "</td>"; 
    print "<td id='"idtorneo'"> <a id='"udlinks'"  href='"uactividades.php?idactividades=$id'">  Edit  </a>   <a id='"udlinks'" onclick='"return confirmDelete()'"  href='"dactividades.php?idactividades=$id'">  Delete  </a></td>";
    print "</tr>"; 
        }
    print "</table>"; 

错误信息提到mysql_query()函数,该函数在您发布的代码中不存在。
所以,要么这些函数被意外地留在代码中,要么你只是发布了错误的代码。
请阅读您的错误信息。它们内容丰富。