在将值从HTML表单传输到PHP文件时,变量的值没有正确存储


Value of variable is not stored correctly while transfering the value from HTML form to PHP file

谢谢Ben,但是现在我面临的另一个问题是,当我将分页添加到代码中时,结果没有第一次显示。请参阅下面代码的后半部分。请帮助

if(isset($_GET['k'])){ $k1 = $_GET['k']; } else { $k1 = ''; }
echo $k1;
    $term = explode(" ", $k1);
$query = "SELECT * FROM database ";
foreach ($term as $each) 
{
    echo $each;
$i++;
    if($i==1)
    {
        $query .= "WHERE keywords LIKE '%$each%' ";
    }
else {
    $query .= "OR WHERE keywords LIKE '%$each%' ";
}
}
$per_pages=3;
$page_query = mysql_query("SELECT COUNT('title') FROM kcpdatabase");
    $pages = ceil(mysql_result($page_query, 0)/$per_pages)  or die
       ($page_query."<br/><br/>".mysql_error());    
       $page = (isset($_GET['page'])) ? (int) 
       ($_GET['page']) : 1;                             
$start = ($page - 1) * $per_pages;  
$query .= "LIMIT $start, $per_pages";

$ourquery1 = mysql_query ($query);
if(!$ourquery1)
echo "No query found";
$row1 = mysql_num_rows ($ourquery1);
if($pages >= 1 && $page <= $pages){ 
    for($x = 1; $x <= $pages; $x++)
    {
        echo '<a href="?page='.$x.'">'.$x.'</a> ';
    }
if ($row1 > 0)
{
    while($result = mysql_fetch_assoc($ourquery1))
    {
           echo "<tr>";
        echo "<td>";
        $title = $result['title'];
        $link = $result['link'];
        $region = $result['region'];
        $sector = $result['sector'];
        $theme = $result['theme'];      
        echo "<td> <a href=$link><h3>$title<h3></a>";
        echo "<h4>Sector: $sector <br>Theme: $theme <br> Region: $region  
                          </td>  </tr>";
    }
}   
}
echo "</tbody>";

下面是我的代码的一部分,我试图搜索在文本框中输入的单词/短语。当我在php文件中使用"$k1 = isset($_GET['k'])"捕获表单中的值时,存储在变量"$each"中的值是"1",而不是用户输入的单词或短语。这会使执行搜索功能的查询变得混乱。请帮我找出错误的位置。

请注意,'k'是在下面的表单代码中定义的文本框的名称。

    <form name="keywordquery" method="get" action="page2.php">
<fieldset class="fieldsetclass"><legend class="legendclass">Search by Keywords</legend>
      <div id="searchbox">
<input type="text" name="k" value="<?php if(isset($_GET['k'])){echo htmlentities($_GET
       ['k']);} ?>" style="border: 1px, thin; width:92%; "/> 
<input type="image" style="margin-bottom: 0; margin-top: 2px;" src="search.png"
      value="submit" />
</div>
</fieldset>
    </form>
    </div>
<table cellpadding="0" cellspacing="0" border="1">
    <tbody>    
<?php
$connection = mysql_connect('', '', '');
if(!$connection)
echo "No database connected";
$dbase = mysql_select_db("", $connection);
if(!$dbase)
echo "No datatable connected";

$k1 = isset($_GET['k']);
echo $k1;
$term = explode(" ", $k1);
$query = "SELECT * FROM datatable ";
foreach ($term as $each) 
{
    echo $each;
$i++;
    if($i==1)
    {
        $query .= "WHERE keywords LIKE '%$each%' ";
    }
else {
    $query .= "OR WHERE keywords LIKE '%$each%' ";
}
}
$k1 = isset($_GET['k']);

它将$k1设置为1,因为它正在检查它是否已设置-在本例中它已设置并且isset()返回true或1。

你想要的是:

if(isset($_GET['k'])){ $k1 = $_GET['k']; } else { $k1 = ''; }

或类似.

这是因为isset()是bool函数,请查看以下链接http://php.net/manual/en/function.isset.php

就这样做

if(isset($_GET['k']))
    $k1 = $_GET['k'];