解析错误javascript代码

大家好，我在下面有一个错误，错误是由最后一部分引起的，谁能指出错误的地方

错误提示:

Parse error: syntax error, unexpected '[', expecting ',' or '; '

本行错误:

 <a> onClick="editstatus('+obj.leaveRecords[aa].idleave +')" </a>

完整代码:

$.ajax({
    type: "POST",
    url: url,
    data: {'wid' : wid},
    success: function(data)
    {
        var obj = jQuery.parseJSON(data);
        $("#WorkerName").text(name + " Leave Application");
        $.each (obj.leaveType, function (bb) {
            $( "#tbody-"+obj.leaveType[bb].idleavetype ).empty();
            $.each (obj.leaveRecords, function (aa) {
                if(obj.leaveType[bb].idleavetype == obj.leaveRecords[aa].idleavetype)
                {
                    var leaveid = obj.leaveRecords[aa].idleave ;
                    console.log(leaveid);
                    $('#tbody-'+obj.leaveType[bb].idleavetype).append('<tr><td>'+obj.leaveRecords[aa].reason+'</td><td>'+obj.leaveRecords[aa].startleaveDate+'</td><td>'+obj.leaveRecords[aa].endleaveDate+'</td><td>'+obj.leaveRecords[aa].nameStatus+'</td><td>'+obj.leaveRecords[aa].name+'</td><td>'+obj.leaveRecords[aa].ApproveOn+'</td><?php if($groupid == 3){ echo '<td> <a> onClick="editstatus('+obj.leaveRecords[aa].idleave +')" </a></td>';  }?></tr>');                                          
                }                                       
            });                                     
        });                                
    }
});