PHP电子邮件表单发件人名称而不是电子邮件


PHP E-mail Form Sender Name Instead Of E-mail?

现在,我已经设置了一个PHP电子邮件表单,一切正常。但是,在测试它时,我只获得发件人的电子邮件地址作为名称。我想要的是发送者的名字,比如:

John Doe

主题主题主题主题

代替:j.doe@website.com

主题主题主题主题

下面是代码…

有人能帮我一下吗?谢谢。PHP:

<?php
if(isset($_POST['email'])) {
    // EDIT THE 2 LINES BELOW AS REQUIRED
    $email_to = "ricky@rickytsang.ca";
    $email_subject = $_REQUEST['subject'];

    function died($error) {
        // your error code can go here
        echo "We are very sorry, but there were error(s) found with the form you submitted. ";
        echo "These errors appear below.<br /><br />";
        echo $error."<br /><br />";
        echo "Please go back and fix these errors.<br /><br />";
        die();
    }
    // validation expected data exists
    if(!isset($_POST['full_name']) ||
        !isset($_POST['email']) ||
        !isset($_POST['subject']) ||
        !isset($_POST['message'])) {
        died('We are sorry, but there appears to be a problem with the form you submitted.');      
    }
    $full_name = $_POST['full_name']; // required
    $email_from = $_POST['email']; // required
    $subject = $_POST['subject'];
    $message= $_POST['message']; // required
    $error_message = "";
    $email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+'.[A-Za-z]{2,4}$/';
  if(!preg_match($email_exp,$email_from)) {
    $error_message .= 'The e-mail you entered does not appear to be valid.<br />';
  }
    $string_exp = "/^[A-Za-z .'-]+$/";
  if(!preg_match($string_exp,$full_name)) {
    $error_message .= 'The name you entered does not appear to be valid.<br />';
  }
  if(strlen($message) < 2) {
    $error_message .= 'The message you entered doee not appear to be valid.<br />';
  }
  if(strlen($error_message) > 0) {
    died($error_message);
  }
    $email_message = "Form details below.'n'n";
    function clean_string($string) {
      $bad = array("content-type","bcc:","to:","cc:","href");
      return str_replace($bad,"",$string);
    }
    $email_message .= "Full Name: ".clean_string($full_name)."'n";
    $email_message .= "E-mail: ".clean_string($email_from)."'n";
    $email_message .= "Subject: ".clean_string($subject)."'n";
    $email_message .= "Message: ".clean_string($message)."'n";

// create email headers
$headers = 'From: '.$email_from."'r'n".
'Reply-To: '.$email_from."'r'n" .
'X-Mailer: PHP/' . phpversion();
@mail($email_to, $email_subject, $email_message, $headers); 
?>
<!-- include your own success html here -->
Thank you for contacting us. We will be in touch with you very soon.
<?php
}
?>

在您的4行$email_message .= ...之后添加一行:

$email_from = $full_name.'<'.$email_from.'>';

那么您需要以这种形式:

"John Doe <j.doe@website.com>"

通常你只需要像这样重新格式化from地址:

"Ricky, Dear" <dearricky@yahoo.com>
http://php.net/manual/en/function.mail.php

在header中,你必须像这样设置From header:

<?php
...
$headers = 'From: ' . clean_string($full_name) . ' <' . clean_string($email_from) . ">'r'n";
..
?>

谢谢刺激!

所以,你的整个代码部分看起来像这样:
// prepare email body text
$message = "";
$message .= "Thanks for registering .....";
$message .= "'n";
$message .= "More stuff here";
$headers = "From: John Smith <info@yourcoolsite.com>";

mail($recipientemail, "Hey thanks for joining!", $message, $headers);

然后电子邮件接收者将在他们的收件箱中看到这样一封电子邮件:

FROM: John Smith

主题:嘿,谢谢你的加入!

消息:感谢您注册.....这里有更多内容

您可以这样设置电子邮件地址

$email_to = "Ricky <ricky@rickytsang.ca>";
http://php.net/manual/en/function.mail.php

改变这4行

 $full_name = $_POST['full_name'];
    $email_from = $_POST['email'];
    $subject = $_POST['subject'];
    $message= $_POST['message'];

:

 $full_name = $_POST['full_name'];
    $email_from = $_POST['email'];
    $subject = $_POST['subject'];
    $message= '"' . $full_name . '" <' . $_POST['message'] . '>';

请确保你复制粘贴这个

Drupal电子邮件表单发件人名称代替电子邮件与域基础?

的例子:

function hook_mail_alter(&$message) {
if($message['id'] == "put_id" && $domain_id == 368){
$default_from = variable_get('site_mail', ini_get('sendmail_from'));
if($message['from'] == $default_from){
$message['from'] = '"'. variable_get('site_name', 'Drupal') .'" <'. 
$default_from .'>';
$message['headers']['From'] = $message['from'];
}
}
}