是否可以用另一个替换和数组?
$databas= array("data1", "data2", "data3", "data4");
$replace_datbas= array("Estimate","Market","Assesments","Products");
foreach($databas as $data){
mysql_query("SELECT * FROM doc WHERE $data='1')"
foreach($replace_databas as $replace_data){
$data=$replace_data
echo"$data";
}
}
编辑我需要替换foreach循环中的数组,因为我不能在它之前完成,因为我需要在替换它之前将$database数组添加到我的mysql_query中。
是的,您可以使用引用:
$database = array("data1", "data2", "data3", "data4");
$replace_datbase = array("Estimate","Market","Assesments","Products");
foreach($database as &$data){
foreach($replace_datbase as $replace_data){
$data = $replace_data;
}
}
但你可能是这个意思(上面的内部foreach没有意义——$data
的值总是$replace_database
的最后一个值(:
$database = array("data1", "data2", "data3", "data4");
$replace_datbase = array("Estimate","Market","Assesments","Products");
foreach($database as $index => &$data){
$data = $replace_data[$index];
}
是,使用如下:
foreach($databas as $key=>$data)
{
$databas[$key] = $replace_databas[$key];
}
$databas = $replace_datbas;
要么我误解了你的要求,要么你把这种方式搞得太复杂了。
您可以使用array_replace-
$databas= array("data1", "data2", "data3", "data4");
$replace_datbas= array("Estimate","Market","Assesments","Products");
$result = array_replace($dtabas, $replace_databas);
请记住,此将第一个数组的值替换为第二个数组的具有相同键的值