我怎样才能得到我的输入表单的值是一个javascript/php变量


how can i get the value of my input form be a javascript/php variable?

我不能得到这段代码的最后一行的值是静态的。我需要对它进行硬编码,这样当他们下拉菜单并选择时,它会获取该值并将其放入动作脚本中。

帮忙吗?

<select id="yo5" onChange="asdf90()"><option>// Let the Page Refresh for each Pick Please!</option>
    <option id="yo4" value="<?php echo $test1 ?>"><?php echo $test1 ?></option>
    <option value="<?php echo $test2 ?>"><?php echo $test3 ?></option>
    <option><?php echo $test4 ?></option>
    <option><?php echo $test5 ?></option>
    <option><?php echo $test6 ?></option>
    <option><?php echo $test7 ?></option>
    <option><?php echo $test8 ?></option>
    <option><?php echo $test9 ?></option>
    <option><?php echo $test10 ?></option>
</select>
<script type = "text/javascript">
    function asdf90()
    {
        elem = <?php $test1 ?>;
        if(document.getElementById('yo5').value = elem)
        {
            alert('hi');
        }
    }
</script>       

<form method="post" action="<?php echo network_admin_url('site-new.php?action=add-site'); ?>">
<div id="nonexsist4"><input name="blog[domain]" type="hidden" value="" /></div>

在echo语句后面加上分号。

<option><?php echo $test9; ?></option>

使用==运算符,而不是=

if(document.getElementById('yo5').value == elem)

代码有几个错误。我引用正确的代码:

<select id="yo5" onChange="asdf90()">
    <option id="yo4" value="<?php echo $test1; ?>"><?php echo $test1; ?></option>
    <option value="<?php echo $test2; ?>"><?php echo $test3; ?></option>
    <option><?php echo $test4; ?></option>
    <option><?php echo $test5; ?></option>
    <option><?php echo $test6; ?></option>
    <option><?php echo $test7; ?></option>
    <option><?php echo $test8; ?></option>
    <option><?php echo $test9; ?></option>
    <option><?php echo $test10; ?></option>
</select>
<script type = "text/javascript">
function asdf90()
{
    var elem = "<?php echo $test1; ?>";
    if(document.getElementById('yo5').value == elem)
    {
        alert('hi');
    }
}
</script>