表单选择选项,不能正确获取值和显示文本


Form select option, can't get the value and display text right

我试图生成一个简单的下拉列表(Laravel 5),其中每个选项的值是我的businesslocations表行的ID,显示的文本由多列数据(address_1, address_2, city)组成,取自每行。

In my controller

public function create()
{       
    $businesslocations = Businesslocation::where('businesslocations.business_id', '=', 'Auth::user()->business_id)->get();
    return view('client.create')->with(['businesslocations' => $businesslocations]);
}

这里是我在create.blade.php中的位置

{!! Form::label('businesslocation_id', 'Business location:') !!}
@foreach($businesslocations as $key => $businesslocation)
    {!! Form::select('businesslocation_id',  $businesslocations, null, ['class' => 'form-control']) !!}
@endforeach

显示值为0:

<label for="businesslocation_id">Business location:</label>
<select class="form-control" id="businesslocation_id" name="businesslocation_id"><option value="0">{&quot;id&quot;:&quot;3&quot;,&quot;business_id&quot;:&quot;7&quot;,&quot;address_1&quot;:&quot; &quot;,&quot;address_2&quot;:&quot; &quot;,&quot;city&quot;:&quot; &quot;,&quot;created_at&quot;:&quot;2015-07-13 15:59:19&quot;,&quot;updated_at&quot;:&quot;2015-07-13 15:59:19&quot;}</option></select>

我正在寻找这样的值="id"和显示文本="address_1 address_2城市"为每个选项。不确定要用什么语法

<label for="businesslocation_id">Business location:</label>
<select class="form-control" id="businesslocation_id" name="businesslocation_id"><option value="1">Business location 1 - address_1 address_2 city</option><option value="2" selected="selected">Business location 2 - address_1 address_2 city</option></select>

查询生成器可以使用"lists"方法-所以如果您使用sql返回business_id为"id"和address1 + address2 + city为"name"

SELECT `businesslocation_id` as `id`, 
CONCAT_WS(" ", `address1`, `address2`) AS `name` FROM `businesslocation`
然后返回一个列表——类似于:
$businesslocations = Businesslocation::where('businesslocations.business_id', '=', 'Auth::user()->business_id)
->get()
->lists('name','id'); 
(This is untested)

那么Eloquent将知道如何处理该名称,id并相应地显示它,如果你坚持:

{!! Form::select('businesslocation',  $businesslocations, null, ['id'=> 'businesslocation','class' => 'form-control']) !!}

基本上如果你想用Laravel的方式做你需要传递name和id给select下拉列表。

也就是说,您还可以为您的businesslocation模型添加一个功能:

public function getFullAddressAttribute()
{
    return $this->business->address1 . ' ' . $this->business->address2 . ' ' . $this->business->city;
}

然后

$businesslocations = Businesslocation::where('businesslocations.business_id', '=', 'Auth::user()->business_id)
->get()
->lists('fullAddress','id'); 

希望这能指引你走向正确的方向!需要注意的是,我还没有测试过上面的代码。

使用常规HTML生成选项,效果很好。

{!! Form::label('businesslocation_id', 'Business location:') !!}
    <select class="form-control" id="businesslocation_id" name="businesslocation_id">
    @foreach($businesslocations as $key => $businesslocation)
        <option value="{{$businesslocation->id}}">{{$businesslocation->address_1}} {{$businesslocation->address_2}} {{$businesslocation->city}}</option>
    @endforeach
    </select>