请求工作在phpadmin，但不是在我的php代码

让我再举一个例子…我不能在php中创建这个视图(而我可以在phpmyadmin)

$sql="CREATE VIEW ratings.rtgemissfitch AS
SELECT derivedtable. ISIN
FROM
(SELECT ISIN, MAX(Date_Notation_Emission) FROM ratings.ratingsemissionfitch as derivedtable GROUP BY ISIN) ";

但是我可以在php中这样做:

$sql="CREATE VIEW ratings.rtgemissfitch AS
(SELECT ISIN, MAX(Date_Notation_Emission) FROM ratings.ratingsemissionfitch as derivedtable GROUP BY ISIN) ";

我真的不明白，首先，对不起我的英语，我是法国人…我真的不明白为什么在phpadmin上运行的请求在我的php代码中不起作用…可能是派生表…所以，我希望得到惠誉的最后评级:phpmyadmin中的SQL请求工作完美:

SELECT `DBFITCH`.`ISIN`, `RATING_FITCH`as FITCH_RTG
FROM
  (SELECT `ISIN`, MAX(`RATING_DATE`) as LastUpdate 
  FROM `ratings`.`ratingsemissionfitch` GROUP BY ISIN) as LAST
  INNER JOIN `ratings`.`ratingsemissionfitch` as DBFITCH
  ON
  DBFITCH.`ISIN`= LAST.`ISIN` 
  AND DBFITCH.`RATING_DATE`=LAST.LastUpdate 

在php中，以下代码不能运行:

$sql="CREATE VIEW ratings.rtgemissfitch AS 
SELECT DBFITCH.ISIN, RATING_FITCH as FITCH_RTG
FROM 
  (SELECT ISIN, MAX(RATING_DATE) as LastUpdate 
  FROM ratings.ratingsemissionfitch GROUP BY ISIN) as LAST
  INNER JOIN ratings.ratingsemissionfitch as DBFITCH
  ON
  DBFITCH.ISIN= LAST.ISIN 
  AND DBFITCH.RATING_DATE=LAST.LastUpdate"; 
  $req = $bdd->exec($sql);

让我再举一个例子…

我不能在php中创建这个视图(而我可以在phpmyadmin)

$sql="CREATE VIEW ratings.rtgemissfitch AS
SELECT derivedtable. ISIN
FROM
(SELECT ISIN, MAX(Date_Notation_Emission) FROM ratings.ratingsemissionfitch as derivedtable GROUP BY ISIN) ";

但是我可以在php中这样做:

$sql="CREATE VIEW ratings.rtgemissfitch AS
(SELECT ISIN, MAX(Date_Notation_Emission) FROM ratings.ratingsemissionfitch as derivedtable GROUP BY ISIN) ";

我真的不明白…提前感谢，

CREATE VIEW