PHP格式字符串


Format string in PHP

我有下面的代码,这让我的文件路径为voicetube/record/1985150721112615但我只需要1985150721112615爆炸前两个文件夹,请帮助我这个

$sql = "SELECT filePath FROM user_recordings ORDER BY recordDate ASC";
$result = mysql_query($sql);
$var = array();
while ($row = mysql_fetch_array($result)) 
{
    $var[] = $row['filePath'];
}

您正在查找basename();

   $var[] = basename($row['filePath']);

您可以使用explode函数,并获取它的最后索引。

while ($row = mysql_fetch_array($result)) 
{
    $arr = explode('/', $row['filePath']);
    $var[] = $arr[count($arr) -1];
}